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anonymous

  • one year ago

Okay, so I've got another log question, except the log bases are different. That difference is making me pretty confused. 2log4(9) - log2(3)

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  1. CGGURUMANJUNATH
    • one year ago
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    |dw:1440359012266:dw|

  2. CGGURUMANJUNATH
    • one year ago
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    |dw:1440359062943:dw|

  3. IrishBoy123
    • one year ago
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    \(2log_4(9) - log_2(3)\) yep?

  4. anonymous
    • one year ago
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    Yep :)

  5. IrishBoy123
    • one year ago
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    so you are now base switching?

  6. anonymous
    • one year ago
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    I believe so...

  7. anonymous
    • one year ago
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    (I'm finally on a computer so I can actually use proper equations yay)

  8. IrishBoy123
    • one year ago
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    \(\huge \log_b a = {\log_d a \over \log_d b}\)

  9. IrishBoy123
    • one year ago
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    so you have options here

  10. anonymous
    • one year ago
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    so what would be the common base? log 2?

  11. IrishBoy123
    • one year ago
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    dunno for sure, haven't done this in ages, but 2 sounds like a good way to start

  12. IrishBoy123
    • one year ago
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    you get a simple answer with bas 2 am pretty sure that @CGGURUMANJUNATH 's drawings are really helpful too but that scrawl does my head in

  13. anonymous
    • one year ago
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    So the final answer is |dw:1440360586587:dw|

  14. IrishBoy123
    • one year ago
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    yep

  15. IrishBoy123
    • one year ago
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    @CGGURUMANJUNATH is doing some really cool stuff with squaring the base itself. that is definitely worth checking out

  16. anonymous
    • one year ago
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    Yeah :D

  17. anonymous
    • one year ago
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    hanks for helping me out everyone :D

  18. anonymous
    • one year ago
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    Thanks*

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