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anonymous
 one year ago
Could anyone help with this activity I have to do? It's trigonometry
anonymous
 one year ago
Could anyone help with this activity I have to do? It's trigonometry

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'd really appreciate it if someone could explain so I can figure it out . I'm terrible at trig . I'm taking an algebra 2 class and apparently trig is apart of algebra 2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@jim_thompson5910 could you help me with this ? :/

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4Your worksheet is a bit misleading. It says that B = 2pi/(period) but that's only true for sine, cosine, cosecant, secant. It doesn't apply to tangent and cotangent. That rule would be B = pi/(period). Luckily we won't be dealing with tangent or cotangent

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4no it's printed on page 1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0apex is confusing and doesn't do the right information

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4you wrote the correct max elevation what is the min elevation?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it didn't give that . Idk

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4dw:1440386808612:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4dw:1440386828053:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4since the ride starts 10 ft off the ground

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh so it'd be 10 ? lol

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4and that would make the diameter 210  10 = 200 and not 210

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I have the diameter as 200

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4oh nvm I misread that part

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4don't forget the units. When it asks for the time to complete 1 revolution. Don't just write "90". Write "90 seconds". Same applies for the other values too

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4other than that, page 1 looks great

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do the max and min have units ? oh and the diameter ?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4yeah, in this case, "feet"

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4same for the diameter

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay I just wanted to be sure

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4ready for #2 ?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4I'm guessing you haven't started at all? Or do you have an idea where to start?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The graph is where I got confused . I looked over it multiple times and I tried graphing but I just didn't understand

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4At time t = 0 seconds, the height is h = 10 ft So one ordered pair is (0,10) and this is a min  45 seconds later at t = 45, the height moves to h = 210 one max point is (45,210)  another 45 seconds pass by and we're now at t = 90 seconds we're back at the min height again and now at the point (90, 10)

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4they want you to plot these mins and maxes for 2 full cycles

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I always forget how to graph lol . Just one second

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4For #2, they don't want the full graph of the sinusoidal curve (ie they don't want sine or cosine plotted). They just want those discrete points.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so don't plot all three of those points ?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4You do plot those points and any others that I didn't list until you've done 2 full cycles

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4If you start at t = 0, 1 full cycle ends at t = 90 2 full cycles end at t = 180

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1440387875856:dw so it'd look somewhat like that ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that's a horrible drawing I know lol . My mousepad sucks

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4that's ok. You should get something like this (see attached). It looks like you did, so you are correct for #2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do I connect the dots or leave them as is ?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4For #2, they just want the min/max points. That's all. So you leave them as is.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay so that one is done

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4what did you get for #3

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm reading it right now

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wouldn't the top of the ferris wheel be the max ?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4they want halfway to the top though

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4dw:1440388468748:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0would you divide 210 by 2 ?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4you would find the midpoint of h = 10 and h = 210 add the values up and divide by 2: (10+210)/2 = ??

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4`would you divide 210 by 2 ?` only if the starting height was 0

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4yes, that's your midline dw:1440388774233:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so their elevation would be 110 feet ?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4at the midway point, yes

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what do they mean by "use the diameter of the Ferris wheel to determine the correct vertical shift for your modeling function?"

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4well I guess another way to do is to divide the diameter in half 200/2 = 100 the radius is 100. Add that radius to the starting height: 100+10 = 110

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4I like the midpoint method better

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Midpoint takes out a step

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so I'd graph it at 110 ?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4are you still on #3 ? or #4 now?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4yeah you'll have a dashed/dotted line that is horizontal and going through y = 110

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1440389236868:dw so like this ?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4which letter represents the vertical shift? A, B, C, or D?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0uh , how do you figure that out ?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4look back on page 1

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4for # 5, you can find the distance using two methods a) subtract the max and min height, then divide by 2 (max  min)/2 = (21010)/2 = 200/2 = 100 OR b) Find the distance from the center (110) to either the peak or valley Center to peak: 210  110 = 100 Center to valley: 110  10 = 100 either way, the radius of this wheel is 100 ft. This is the amplitude of the sinusoidal curve the amplitude is A, so A = 100

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yeah I just subtracted it and got 100

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0amplitude is distance ?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4the distance from midline to the max or the distance from midline to the min

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4dw:1440389822564:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4or half the distance from the very top to the very bottom dw:1440389869160:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so it just depends on exactly what they're asking ?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4what do you mean?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0or is all just the same ?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4those are 2 different ways to get the same thing

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4so it doesn't matter which path you take

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ooh okay , I just wanted to make sure

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0for 6, do I keep it in terms of pi or simplify it completely ?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4I'd leave it in terms of pi

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4reduce the fraction as much as possible though

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so it'd be \[B=\frac{ 2\pi }{ 90 } = \frac{ \pi }{ 45 }\]

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4which trig function will you use for #7 ? sine or cosine?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4either works, but cosine is actually easier to work with if you graph the parent function y = cos(x), you'll notice it has the peak max point at (0,1). We want the peak max point to happen when t = 45 so that's why C = 45 is the phase shift. We shift everything over 45 units to the right

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4A = 100 B = pi/45 C = 45 D = 110 \[\Large H(t) = A\cos\left(B(tC)\right) + D\] \[\Large H(t) = 100\cos\left(\frac{\pi}{45}(t45)\right) + 110\] attached is the graph

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4you could use sine but the phase shift would be different. Everything else would stay the same

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay , it makes sense

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0in number 8 , what do they mean by horizontal shift ?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4the parent function y = cos(x) has a max when x = 0 but we want to force the max to be when x = 45 so that's why we do a horizontal shift and why C = 45

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4dw:1440390964651:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4dw:1440390975447:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4dw:1440390992114:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So it is 45 . I'm used to shifts when it comes to 2 graphs

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4yeah it's 45 if we use cosine

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Since with cosine x = 0

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4what do you mean?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0idk . I'm probably confusing myself

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so for number 9 , where are they getting at with the parent function being flipped ? I don't even know what the parent function is :/

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4in this case, we used the parent function y = cos(x)

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4it's just the base function that you apply the transformations to

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4A = 100 which is positive, we aren't flipping the function over

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0if it were to be flipped , how would I know that was the case ?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4well I started with y = cos(x) which has A = 1 as a positive number shifting everything over to the right 45 units doesn't flip things

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4I played around with the graph a bit, and I am just realizing that A could be negative, but that changes the phase shift.

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4So there are a few ways to get the h(t) function

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4if A = +100, then the phase shift is C = 45 if A = 100, then the phase shift is C = 0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0But since it's dealing with a ferris wheel , it couldn't have a negative value since you can't go in circles negative times right ?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4t and h can't be negative, but A could be

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4the amplitude is A the absolute value ensures we have a positive amplitude

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4on your worksheet, draw vertical bars around the "A" where it says `A is the amplitude` on page 1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh okay , so it doesn't really matter if it was negative cause it regardless it's going to be positive since it's absolute value ?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4eg: y = 2*cos(x) has an amplitude of 2 = 2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0in the equation on number 10, what's "Af" ?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4I don't see #10 in any of the attachments

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4oh, that's A*f

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4f is the trig function look back at page 1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so it's the amplitude times the trig function ? 100cosx ? or ...

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4yeah like how I wrote above when I wrote out H(t)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0where did you write that ?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4it's buried a bit when I wrote \[\Large H(t) = 100\cos\left(\frac{\pi}{45}(t45)\right) + 110\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oooh okay , I remember

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and t would b 90 , correct ?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4t is just a variable that represents the time in seconds

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4you plug in values of t to get corresponding values of h eg: plug in t = 0 to get h = 10 plug in t = 45 to get h = 210 etc etc

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wait so how exactly is the equation set up ?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4what do you mean?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I plug everything into that equation right ?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4I'd just leave it as \[\Large H(t) = 100\cos\left(\frac{\pi}{45}(t45)\right) + 110\]

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4They want the function or equation that models the curve

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4nope, they just want you to write the equation

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and for number 11 , i use that same equation, I'm just solving for t ?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4correct. replace h(t) with 100 and solve for t

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0To start I'd subtract 110 over to 100 right ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what do I do from there ?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4you should have this \[\Large 100\cos\left(\frac{\pi}{45}(t45)\right) = 10\]

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4now divide both sides by 100

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so it'd be equal to 1/10 ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I feel like decimal is better

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4Then apply the arccosine function to both sides \[\Large \Large \cos\left(\frac{\pi}{45}(t45)\right) = 0.1\] \[\Large \Large \arccos\left(\cos\left(\frac{\pi}{45}(t45)\right)\right) = \arccos(0.1)\] \[\Large \Large \frac{\pi}{45}(t45) = ??\]

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4arccos is \(\Large \cos^{1}\), ie inverse cosine

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4no, that's a common misconception

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4if you want to say 1/cos, you say secant

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4you don't say \(\Large \cos^{1}\) to mean secant \(\Large \cos^{1} \ne \sec\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh okay , so I haven't learned arccos

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4your calculator should have a cos^(1) or arccos button

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so I find arccos0.1

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4yeah what is that numeric value?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4make sure you're in radian mode

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4we will use the negative form to figure out when the height reaches 100 ft for the first time (the +1.67 is used to figure out when the height reaches 100 ft for the second time)

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4so solve for t \[\Large \Large \frac{\pi}{45}(t45) = 1.67\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do I distribute or multiply pi/45 by the recipricol on both sides ?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4I'd multiply by the reciprocal

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so it'd be \[t45=\frac{ 75.15 }{ \pi }\]

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.475.15/pi = 23.9209879 approximately

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4now just one more step to go

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so it would equal 21.08 ?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4I'm getting 21.07901205 with a calculator and geogebra is telling me 21.06521 so it's pretty close

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4so roughly 21 seconds

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I rounded the 21.07901205

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4and desmos says the same thing more or less https://www.desmos.com/calculator/swknd4tau1

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4you'll have to click on the first intersection point between the curve and the line

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You really helped a lot lol . I can finally release some stress . Thank you

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4you're welcome
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