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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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first find the derivative of this function
can you do that?
implicit differentiation. Treat y as a function of x.

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Yes I got 6x^2-3xy'(x)+3y^2y'(x)-3y
= 0
looks good
now its just algebra
Plugging in the points?
make y' the subject then plug in the points
y'(x)
do you know what I mean ?
Yeah like set everything equal to y'(x) right?
yea - like solving for y'(x)
Okay I got -6x^2+3x/-3x3y^2=y'(x)
now its just a matter of plugging in the given values of x and y
There was an error I think my formula is wrong
yes i got a different result foe y'(x)
I got -18
i get -11/7
i might have it wrong as I'm getting tired.
Let me try it again
Oh wait yeah I see where I went wrong I plugged in the wrong points but I got -11/7 now
Thank you!!!!

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