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Jamierox4ev3r
 one year ago
More review! Help appreciated
Jamierox4ev3r
 one year ago
More review! Help appreciated

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Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.14e. Factor the following expression: \[3x ^{\frac{ 3 }{ 2 }} 9x ^{\frac{ 1 }{ 2 }} +6x ^{\frac{ 1 }{ 2 }}\]

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.1I'm pretty lost on this, having to factor with the rational fractions is throwing me into a bit of a loop.

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.1Does anyone have a simple method of doing this by hand? Or do you recommend grabbing a calculator to look for xintercepts so I can factor that way?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hold on i gotta write it :)

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.1fair enough, thank you @PinkiePug

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[3(x \frac{ 1 }{ 2 }  3x \frac{ 1 }{ 2 }+2 x \frac{ 1 }{ 2 }\] this is what i got

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0\[x^{1/2} \implies \sqrt{x}\] \[x^{1/2} \implies \frac{ 1 }{ \sqrt{x} }\] This may be easier to visualize, so we can write it as \[3x^{3/2}9\sqrt{x}+6\frac{ 1 }{ \sqrt{x} }\]

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0Then we can find the common denominator \[\sqrt{x}\]

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0Your numerator should simplify into something better which you can factor

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.1Wait. so are you suggesting that we have to get rid of the negative exponents in order to successfully factor this?

phi
 one year ago
Best ResponseYou've already chosen the best response.2I would factor out 3x^1/2 \[ 3x ^{\frac{ 3 }{ 2 }} 9x ^{\frac{ 1 }{ 2 }} +6x ^{\frac{ 1 }{ 2 }} \\ 3x ^{\frac{ 1 }{ 2 }}\left( x^2 3x +2\right) \]

phi
 one year ago
Best ResponseYou've already chosen the best response.2now you can factor the quadratic

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0Yeah that works to haha :P

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ 3x^29x+6 }{ \sqrt{x} }\] is what you get from my suggestion

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.1oh. so i can factor \(x^{2}3x+2\), since that's the quadratic. Oh wow that's much simpler. So the final answer would be: \(3x^{\Large\frac{1}{2}}\)(x1)(x2)

phi
 one year ago
Best ResponseYou've already chosen the best response.2yes, or put sqr(x) in the denominator it is still ugly. but it's factored

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.1so just so I know, for future problems like this, is it always acceptable to take out a value so that you're left with a quadratic that you can easily factor?

phi
 one year ago
Best ResponseYou've already chosen the best response.2it is a common trick. no guarantees, but something to try

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.1Fair enough. I'll keep that in mind. Thank you very much kind sir
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