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I have to plo\[g(t)=u(7t+\sqrt{3})\] and find at what points the function is discontinuous.

Example:\[f(t)=u(3t-7)\]\[3t-7=0\]\[3t=7\]\[t=\frac{ 3 }{ 7 }\]|dw:1440369141852:dw|

|dw:1440369231308:dw|

Another Example: \[h(t)=u(-3t+7)\]\[-3t+7=0\]\[-3t=-7\]\[t=7/3\]|dw:1440369295368:dw|

http://prntscr.com/883u7t here is the defintion of a unit step function

that is where wherever the shift is taking place is where the discontinuity is

oh that makes more sense, so if I solve for 0, shouldn't I get when t=0?

and from the examples I was given, it seems that at those points is where the shift happens

|dw:1440369613756:dw|

i think you should really be thinking of what a function is and how transformations work

So the shift doesn't always occur when it's at 0?

or only if we follow |dw:1440370174580:dw|

yes I understand all that

yeah thats all u need to know

and the definition of u(t) which u have

|dw:1440370382170:dw|

there will be other places where the function is not defined like this

or suppose they started throwing t into radicals or having abs values in there and stuff like that

Like for the second example, what made the plot switch directions?|dw:1440370886926:dw|