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anonymous
 one year ago
started once
anonymous
 one year ago
started once

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\(\large\color{black}{ \vec{a} =(2,3,4) }\) \(\large\color{black}{ \vec{b} =(4,3,2) }\) find the magnitude of \(\large\color{black}{ \vec{c} }\) if \(\large\color{black}{ \vec{c} =\vec{a}\times \vec{b} }\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i will try it here....

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\(\large\color{black}{ c_x=3\cdot24\cdot3=612=6 }\) \(\large\color{black}{ c_y=4\cdot42\cdot2=164=10 }\) \(\large\color{black}{ c_z=2\cdot32\cdot4=612=6 }\) \(\large\color{black}{ \vec{c}=(6,10,6) }\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\(\large\color{black}{ \vec{c}=\sqrt{36+100+36}=\sqrt{172} }\) and whatever that simplifies to

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0am i doing it right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0misswrote for c_z, the 2•4 part is really 3•4 apologize for typo

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1440381322880:dw \[\left c \right=\sqrt{\left( 6 \right)^2+12^2+\left( 6 \right)^2}=6\sqrt{6}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh, yeah, my mistake it is 12 not 10. i said 164=10 xD
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