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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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\(\large\color{black}{ \vec{a} =(2,3,4) }\) \(\large\color{black}{ \vec{b} =(4,3,2) }\) find the magnitude of \(\large\color{black}{ \vec{c} }\) if \(\large\color{black}{ \vec{c} =\vec{a}\times \vec{b} }\)
i will try it here....
\(\large\color{black}{ c_x=3\cdot2-4\cdot3=6-12=-6 }\) \(\large\color{black}{ c_y=4\cdot4-2\cdot2=16-4=10 }\) \(\large\color{black}{ c_z=2\cdot3-2\cdot4=6-12=-6 }\) \(\large\color{black}{ \vec{c}=(-6,10,-6) }\)

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Other answers:

\(\large\color{black}{ ||\vec{c}||=\sqrt{36+100+36}=\sqrt{172} }\) and whatever that simplifies to
am i doing it right?
misswrote for c_z, the 2•4 part is really 3•4 apologize for typo
|dw:1440381322880:dw| \[\left| c \right|=\sqrt{\left( -6 \right)^2+12^2+\left( -6 \right)^2}=6\sqrt{6}\]
oh, yeah, my mistake it is 12 not 10. i said 16-4=10 xD

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