Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions

|dw:1440370564478:dw|

I really need help on this

\(\cos(3\pi)\)

how'd u get that?

the function is \(\cos(\pi x)\)

can u show me the steps to how you got that equation?

so what do you do after that?

what do you do with the h in the denominator?

we looked at the derivative (the thing with the h) to get the function that we needed.

ooh ok. why is the answer -1?

\(\cos(3\pi)=-1\)

It asks for \(f(3)\) not \(f'(3)\)

I'm not understanding why it's negative

you lost me there

what do you mean?

nvm i didn't read the question correctly
i thought you were supposed to find the limit

can you help me with another question?

Do you understand this one?

i don't

you mean \(\cos(\pi x)\)?

yeah that

what are you confused about @satellite73 ? seems pretty basic intro calc question to me.

maybe I am confused lol

knowing the derivative does not mean you know the function

if f(x)=2+6x-x^2, for what values of x is f'(x) positive?

lol

hehe, I cant think of what else they are asking...

that "plus k" is a killer

can u guys help me with my other question?

\[f(x)=2+6x-x^2\\
f'(x)=6-2x\] solve
\[6-2x>0\]

x<3?

yup

thank you! :)

lol rereading my own remark makes me cringe

it is not you, it is whoever wrote the stupid question