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anonymous
 one year ago
limit as x approaches zero of quantity negative six plus x divided by x to the fourth power.
anonymous
 one year ago
limit as x approaches zero of quantity negative six plus x divided by x to the fourth power.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\(\large\color{slate}{\displaystyle\lim_{x \rightarrow ~0}\frac{6+x}{x^4}}\) this?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\(\large\color{slate}{\displaystyle\lim_{x \rightarrow ~0}\frac{6+x}{x^4}}\) \(\large\color{slate}{\displaystyle\lim_{x \rightarrow ~0}\frac{6}{x^4}+\lim_{x \rightarrow ~0}\frac{x}{x^4}}\) so I don't think you will get anything defined out of the limit

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wait, approaches 6?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh, 6+x! Doesn't matter

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you would be then getting \(\large \displaystyle \lim_{x \rightarrow ~0}\frac{6}{x^4}+\frac{x}{x^4}\) and still DNE

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Wait so which one is it?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it is infinity not zero, i think

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.0I don't believe L'Hopital's rule applies, 6/0 doesn't count as an indeterminate form

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no she meant part 2, but there x's xcancel

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What is that rule though?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that is to differentiate top and bottom, IF you get 0/0 or ∞/∞, when you plug in the value that x approaches into the limit

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0this is L'Hospital's Rule

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Could you guys help me with this?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So for example, I have: \(\large \displaystyle \lim_{x \rightarrow ~0}\frac{\sin(x)}{x}\) and there you would apply this rule (can you tell me why?)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i don't see a reason for onesided limit not to exist (unless the function is totally not on that interval, or if it goes into infinity  asymptote)

Plasmataco
 one year ago
Best ResponseYou've already chosen the best response.0Well x=2 is an asymptote

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.0@phunish well, it's asking for the limit as the function approaches x = 2 from the left, any ideas?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok, you see that the graph has two parts (two sticks :D) right/
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