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anonymous
 one year ago
what are the values of x in this equation? x^(2/5)+x^(1/5)+1=3
answers:
32,1
32,1
32,1
32,1
anonymous
 one year ago
what are the values of x in this equation? x^(2/5)+x^(1/5)+1=3 answers: 32,1 32,1 32,1 32,1

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Theloshua
 one year ago
Best ResponseYou've already chosen the best response.0ummmm okay, so the first thing your gonna do is subtract one from both sides

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Subtract 3 from both sides, because then one side will be 0 and you can factor or use the quadratic equation

Theloshua
 one year ago
Best ResponseYou've already chosen the best response.0\[x ^{\left(\begin{matrix}2 \5\ ?\end{matrix}\right)} + x ^{\left(\begin{matrix}1 \5 \ ?\end{matrix}\right)}=3\]

Theloshua
 one year ago
Best ResponseYou've already chosen the best response.0is that the equation?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the equation is x^(2/5)+x^(1/5)+1=3

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how do i subtract 3 from the left side? do i plug in the numbers first?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0x^(2/5) + x^(1/5) + 1 = 3 x^(2/5) + x^(1/5)  2 = 0

Theloshua
 one year ago
Best ResponseYou've already chosen the best response.0oh wait, your right :D do your thing XD

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you can do a change of variables. Let u = x^(1/5), then the equation becomes u² + u  2 = 0 Solve the quadratic equation for u Then go back and solve for x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so its 32 and 1 that equals 3 right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no it doesn't work that way. The solutions have to work individually. You can't mix them. Factor the quadratic equation I put above to get solutions for u

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0u^2+u=2 u(u+1)=2 u=1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how to i solve for x? x^(1/5)=1? is that how i do it?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0if that is the value of u, then yes, there should be 2 values for u though

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how do I get two values for u then?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0they aren't using the same kind of numbers i am. what am i doing wrong?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Refer to the attachment from Mathematica 9.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@robtobey how does that help me?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It provides the right answer.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you didn't factor that right. the video @billj5 posted shows you how to factor. @robtobey gave you the answer

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0where is the answer in it?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0none of your options are going to work because 1 is the only solution to this equation.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that's what i thought but it doesn't give me an option for just 1.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok. let's see if we can find another Factor this u² + u  2 = 0 What 2 numbers multiply to 2 and add to 1?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Quadratic equations have 2 solutions, so we need TWO numbers. Look at the factors of 2 and then figure out which pair adds to 1.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i still don't understand any of this. :(

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok. What did you get?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah that's right :)
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