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anonymous

  • one year ago

Help w/ expo equations

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  1. Theloshua
    • one year ago
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    no, incorrect

  2. anonymous
    • one year ago
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    okay, but just so you know, that's the equation I have to use, so that part can't be wrong. I guess my answer is the wrong part.

  3. Theloshua
    • one year ago
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    because you divided on both sides, which you cant do, because the x isnt a multiplication value, its a squared value

  4. Theloshua
    • one year ago
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    the equation is right, you just used it incorrectly

  5. anonymous
    • one year ago
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    okay. On my paper there is no ^ to indicate anything it's just written as I wrote it.

  6. anonymous
    • one year ago
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    so maybe that's where I got confused.

  7. Theloshua
    • one year ago
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    |dw:1440374565771:dw|

  8. Theloshua
    • one year ago
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    is that what the equation looks like?

  9. Theloshua
    • one year ago
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    okay, i believe your first step was to divide the 20000 on both sides, correct?

  10. anonymous
    • one year ago
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    yeah I think so

  11. anonymous
    • one year ago
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    I'm thinking my answer is 4 years now.

  12. Theloshua
    • one year ago
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    okay, thats correct i believe

  13. Theloshua
    • one year ago
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    can you please tell me what you did to solve just to make sure?

  14. anonymous
    • one year ago
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    Okay on the next page, it says that it the answer to it was 4 years. So I did it right the 2nd time.

  15. anonymous
    • one year ago
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    Thanks for helping me a bit. :) Much appreciated. I almost put down the wrong answer.

  16. Theloshua
    • one year ago
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    okay, no probs :D

  17. anonymous
    • one year ago
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    Refer to the attachment from Mathematica 9.

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  18. anonymous
    • one year ago
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    this question is close, when I clicked close, it didn't do it apparently so yeah.

  19. anonymous
    • one year ago
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    \[10,000 = 20,000 (0.85)^x\] \[\frac{1}{2}=.85^x\] is a start

  20. anonymous
    • one year ago
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    weird internet connection or something

  21. anonymous
    • one year ago
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    solve via \[x=\frac{\ln(.5)}{\ln(.85)}\] and a calculator

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