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Compare the functions shown below:

the rate of change of that line is a constant
it is the slope
do you know it?

@satellite73 Would 0.5/3 be the slope? I'm pretty bad at this, haha

Sorry, 1.5*/3

So what is f(3) for f(x)?

f(3)=((3)+3)^2-2, am I doing okay, so far?

Yup, exactly!

f(3)=(9)^2-2 - > f(3)=81-2 -> 79?

Not quite, 3+3 = 6 :P

Yup that's good!

now find f(-1)

Yay! ^^

|dw:1440381614071:dw|

perfect now we have \[f(x) = \frac{ 34-2 }{ 3-(-1) }\]

\[f(x)=32/4?\]

Yes simplify it

I should say m = that not f(x) xD but same thing

16/2

m = 34/4 = 16/2 keep going

8/1

Yup m = 8 for f(x)

|dw:1440378413551:dw| what are these two points?

We're doing g(x) now

Computer is slowing down - sorry, sorry x-x The two points are (-1,-2) and (3,0)

All right... |dw:1440382384897:dw|

Yes! 1/2 is good

So we have slope for f(x) = 8, g(x) = 1/2, now lets find the slope for h(x)

Not sure how to find the slope for that one... doesn't seem to be in my notes

Just read the table and apply the formula

|dw:1440379170633:dw|

The formula \[m=y2-y1/x2-x1\]? Just making sure

yup

|dw:1440383049367:dw|

g(x),f(x), h(x)!

Looks good :)

Thanks so much, you're really a life-saver!

Yw :)

Oh this was a test...we can't help on tests sorry.