## jmartinez638 one year ago Find the points of intersection of the graph of the following equations: y = (sqrt3/3x) + 1 x^2 + (y-1)^2 = 4

1. anonymous

$y=\frac{\sqrt 3}{3x}+1$?

2. jmartinez638

That is, $y = \frac{ \sqrt3 }{ 3 }x + 1$ and $x^2 + (y-1)^2 = 4$

3. mathmate

Hints: Given: $$y = \frac{ \sqrt3 }{ 3 }x + 1$$ substitute into the second equation: $$x^2 + (y-1)^2 = 4$$ $$x^2 + ( \frac{ \sqrt3 }{ 3 }x + 1-1)^2 = 4$$ Simplify and solve for x (two roots, symm. about y-axis)