A bike and skate shop rents bike for $21 per day and pairs of skates for $20 per day. To remain viable, the shop needs to make at least $362 per day from bike and skate rentals combined. If they rent twice as many bikes as they do pairs of skates, what is the least number of pairs of skates they need to rent each day to make their minimum? It needs to be in inequality form and I don't understand how to put it in that form for this problem.

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A bike and skate shop rents bike for $21 per day and pairs of skates for $20 per day. To remain viable, the shop needs to make at least $362 per day from bike and skate rentals combined. If they rent twice as many bikes as they do pairs of skates, what is the least number of pairs of skates they need to rent each day to make their minimum? It needs to be in inequality form and I don't understand how to put it in that form for this problem.

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Let x be the amount of bikes and y be the amount of skates. So then they make 21x from bikes and 20y from skates
The total amount they make has to be AT LEAST ( ≥ ) $362. So, \[21x+20y \ge 362\]
twice as many bikes as pairs of skates mean \[x=2y\] Substitute back into the inequality to get \[21(2y)+20y \ge 362\] Solve for y

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Thank you! I got it figured out! :)
you're welcome

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