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anonymous

  • one year ago

seven apples and one orange cost 98 cents. two apples and three oranges cost 66 cents. find the cost of one apple and one orange

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  1. anonymous
    • one year ago
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    i bet you are supposed to solve \[7x+y=98\\ 2x+3y=66\] where \(x\) is the number of apples and \(y\) is the number of oranges

  2. anonymous
    • one year ago
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    what next ?

  3. zzr0ck3r
    • one year ago
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    I would suggest either 1) multiplying the first equation by \(-3\) and then adding the two equations. 2) Solve the first equation for \(y\) and plug that into the second equation.

  4. radar
    • one year ago
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    Actually x is the cost of one apple and y is the cost of 1 orange.

  5. radar
    • one year ago
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    I would use substitution to solve. Take the first equation 7x + y = 98 and express y in terms of x getting: y = -7x + 98 Did you follow that with understanding?

  6. radar
    • one year ago
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    It appears that you went off line so I would assume you can take it from here.

  7. radar
    • one year ago
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    It is now simply a matter to substitute for y in the second equation and solve for x, then nail y.

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