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anonymous
 one year ago
seven apples and one orange cost 98 cents. two apples and three oranges cost 66 cents. find the cost of one apple and one orange
anonymous
 one year ago
seven apples and one orange cost 98 cents. two apples and three oranges cost 66 cents. find the cost of one apple and one orange

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i bet you are supposed to solve \[7x+y=98\\ 2x+3y=66\] where \(x\) is the number of apples and \(y\) is the number of oranges

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.1I would suggest either 1) multiplying the first equation by \(3\) and then adding the two equations. 2) Solve the first equation for \(y\) and plug that into the second equation.

radar
 one year ago
Best ResponseYou've already chosen the best response.0Actually x is the cost of one apple and y is the cost of 1 orange.

radar
 one year ago
Best ResponseYou've already chosen the best response.0I would use substitution to solve. Take the first equation 7x + y = 98 and express y in terms of x getting: y = 7x + 98 Did you follow that with understanding?

radar
 one year ago
Best ResponseYou've already chosen the best response.0It appears that you went off line so I would assume you can take it from here.

radar
 one year ago
Best ResponseYou've already chosen the best response.0It is now simply a matter to substitute for y in the second equation and solve for x, then nail y.
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