anonymous
  • anonymous
seven apples and one orange cost 98 cents. two apples and three oranges cost 66 cents. find the cost of one apple and one orange
Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
i bet you are supposed to solve \[7x+y=98\\ 2x+3y=66\] where \(x\) is the number of apples and \(y\) is the number of oranges
anonymous
  • anonymous
what next ?
zzr0ck3r
  • zzr0ck3r
I would suggest either 1) multiplying the first equation by \(-3\) and then adding the two equations. 2) Solve the first equation for \(y\) and plug that into the second equation.

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radar
  • radar
Actually x is the cost of one apple and y is the cost of 1 orange.
radar
  • radar
I would use substitution to solve. Take the first equation 7x + y = 98 and express y in terms of x getting: y = -7x + 98 Did you follow that with understanding?
radar
  • radar
It appears that you went off line so I would assume you can take it from here.
radar
  • radar
It is now simply a matter to substitute for y in the second equation and solve for x, then nail y.

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