help!

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Jason has two bags with 6 tiles each. The tiles in each bag are shown below: Six squares are numbered sequentially from 1 to 6. Without looking, Jason draws a tile from the first bag and then a tile from the second bag. What is the probability of Jason drawing the tile numbered 5 from the first bag and an odd tile from the second bag? 3 over 6 4 over 6 3 over 36 4 over 36
what is the probability he draws a 5 from bag one?

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um 2
??
where on earth did you get that from? a probability is a number between zero and one it can never be 2 lets go slow
how many tiles are in the bag?
because i dont get it :(
that is clear, so lets take it one step at a time how many tiles are in bag one?
6 tiles are in each bag
6 tiles in bag one out of those six, how many are labelled "5"?
3
there are 3 tiles labelled "5" in bag one?
seems unlikely, since the question says "Six squares are numbered sequentially from 1 to 6. "
1 Attachment
yeah i get the picture the question is "how many tiles are labelled "5"?" this is not a trick question
theres only 1
whew!!
1 right, not 3
right
ok so there is 1 labelled 5, and 6 all together what is the probability you pick the 5?
2?
guess my words above did not help a probability is a number between zero and one, it is never two it is the ration of the number of fives to the total number of tiles, i.e one out of six or as a fraction \[\huge \frac{1}{6}\]
we are not done yet though
ok whats next
how many odd tiles are in the second bag?
3
right! and there are 6 tiles in the bag yes?
yes
ok now please to not say "2" what is the probability that you pick an odd tile out of the second bag
3
repeat after me a probability cannot be larger than 1
ok so 1
how many odd tiles?
3
how many tiles total?
6
ratio of the number of odd tiles to total number of tiles?
1/6?
how many odd tiles?
\[\frac{\text{number of odd tiles}}{\text{total number of tiles}}\]
3 so 3/6?
yay!!
ok one more step
you want the probability of both of those, first is a 5 AND second is odd we have the probability of each probability of first one is \(\frac{1}{6}\) probability of second one is \(\frac{3}{6}\) take the numbers and multiply them i.e. \[\frac{1}{6}\times \frac{3}{6}\]
is3/6
that is not how you multiply fractions is it? multiply means multiply top and bottom
the answer is \[\frac{ 3 }{6 }\]
\[\frac{1}{6}\times \frac{3}{6}=\frac{1\times 3}{6\times 6}\]
oh sorry 3/12
\[6\times 6=?\]
12
no \(2\times 6=12\) but \(6\times 6\neq 12\)
36
whew that is much better so now what is \[\frac{1}{6}\times \frac{3}{6}\]?
3/36 :) can you help me with more please? ill tag you !
yes got it on planet earth we call that \[\frac{1}{12}\] but that is not one of your answer choices, so go witih \(\frac{3}{36}\)

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