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anonymous
 one year ago
Question 10 18.01 Practice Questions for Exam 2... What is going on in the solution? I follow everything to do with putting all the y on the left of the equation and all the x on the right of the equation... but then boom they use tan instead of integrating??? What is happening
anonymous
 one year ago
Question 10 18.01 Practice Questions for Exam 2... What is going on in the solution? I follow everything to do with putting all the y on the left of the equation and all the x on the right of the equation... but then boom they use tan instead of integrating??? What is happening

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phi
 one year ago
Best ResponseYou've already chosen the best response.0the integral evalutes to \[ \int \frac{dx}{1+x^2}= \tan^{1} x +C\] See the notes for lecture 5 http://ocw.mit.edu/courses/mathematics/1801singlevariablecalculusfall2006/lecturenotes/lec5.pdf where they derive \[ \frac{d}{dx} \tan^{1} x = \frac{1}{1+x^2}\] and if we take the integral of both sides, we get the formula they used.
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