At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
@anitasonia98 would you mind helping me w a few more questions?? sorry i keep tagging you im just new and you have been the most helpful!
It's ok! Oxidation means that you're losing electrons :) So which choice would it be?
@anitasonia98 would it be choice B?
In choice B, Mn is gaining electrons (it has a charge of +7 in MnO4-, and then it has a charge of +4 in MnO2).
When you lose electrons, the positive number becomes larger. :)
so its C?!
@anitasonia98 could it be C and D?
C is it :)
Wait, hold on
It's C. :) A different reaction is going on in D, I think.
@anitasonia98 okay thanks! i have like 2 or 3 more questions i need help with is that cool?
Np! And that's fine :)
@anitasonia98 1.) H2O and OH- are added as needed to the half-reaction equations to make the number of oxygen and hydrogen atoms balance. Divide the chemical equation into two half-reaction equations, identifying which half-reaction is oxidation and which is reduction. H2O and H+ are added as needed to the half-reaction equations to make the number of oxygen and hydrogen atoms balance. Multiply each term in one of the half-reaction equations by a factor that will make the number of electrons lost (in the oxidation) equal to the number of electrons gained (in the reduction). 2.) Consider the following unbalanced redox reaction: I2 → IO3- How many water molecules are needed for balancing? 3 on the reactant side 3 on the product side 2 on the product side 2 on the reactant side 3.) Which of the following is a use for electrolytic cells? electroplating rechargeable batteries car batteries watch battery
I haven't done redox reactions in a long time :o As for #3, it would be rechargeable batteries :3
I've kinda forgotten how to do redox, whoops. http://www.shodor.org/unchem/advanced/redox/
@anitasonia98 thank you! :)
Sorry about not being able to answer #1 and #2 :o I haven't done those in such a long time.
That seems to be a slightly better explanation for how to figureout redox :o