@anitasonia98 would you mind helping me w a few more questions?? sorry i keep tagging you im just new and you have been the most helpful!
It's ok! Oxidation means that you're losing electrons :) So which choice would it be?
@anitasonia98 would it be choice B?
In choice B, Mn is gaining electrons (it has a charge of +7 in MnO4-, and then it has a charge of +4 in MnO2).
When you lose electrons, the positive number becomes larger. :)
so its C?!
@anitasonia98 could it be C and D?
C is it :)
Wait, hold on
It's C. :) A different reaction is going on in D, I think.
@anitasonia98 okay thanks! i have like 2 or 3 more questions i need help with is that cool?
Np! And that's fine :)
@anitasonia98 1.) H2O and OH- are added as needed to the half-reaction equations to make the number of oxygen and hydrogen atoms balance. Divide the chemical equation into two half-reaction equations, identifying which half-reaction is oxidation and which is reduction. H2O and H+ are added as needed to the half-reaction equations to make the number of oxygen and hydrogen atoms balance. Multiply each term in one of the half-reaction equations by a factor that will make the number of electrons lost (in the oxidation) equal to the number of electrons gained (in the reduction). 2.) Consider the following unbalanced redox reaction: I2 → IO3- How many water molecules are needed for balancing? 3 on the reactant side 3 on the product side 2 on the product side 2 on the reactant side 3.) Which of the following is a use for electrolytic cells? electroplating rechargeable batteries car batteries watch battery
I haven't done redox reactions in a long time :o As for #3, it would be rechargeable batteries :3
I've kinda forgotten how to do redox, whoops. http://www.shodor.org/unchem/advanced/redox/
@anitasonia98 thank you! :)
Sorry about not being able to answer #1 and #2 :o I haven't done those in such a long time.
That seems to be a slightly better explanation for how to figureout redox :o