anonymous
  • anonymous
Need help with square root problem please :)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
|dw:1440383921670:dw|
anonymous
  • anonymous
sorry if you cant read this. but i multiped 7 and 5 and got 35 multiplied 2 and 6 and got the square root of 12 and i multiplied 7 and 4 and got -28 and i tried multiplying 7 and the square root of 2 but it gives me 14 and everytime i try to simplify it doesnt make sense and doesnt give me the right answer.
anonymous
  • anonymous
the answer is 70 and square root of 3 -56 but how is it 56?

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anonymous
  • anonymous
\[70\sqrt{3}-56\] okay thats the answer
anonymous
  • anonymous
Using the distributive property\[7\sqrt{2}\left( 5\sqrt{6}-4\sqrt{2} \right)\]\[=35\sqrt{12} - 28\sqrt{4}\]Does this help?
anonymous
  • anonymous
but dont you multiply the 7 and the square root of 2?
anonymous
  • anonymous
It helps, but im just wondering why i dont multiply it
anonymous
  • anonymous
You're multiplying \(7\sqrt{2}\) by \(4\sqrt{2}\). You multiply the coefficients together and the radicals together to give \(28\sqrt{4}\) which, of course, can be simplified.
anonymous
  • anonymous
oh! okay i understand!! thank you so much. :)
anonymous
  • anonymous
In general\[a \sqrt{b} \times c \sqrt{d} = ac \sqrt{bd}\]
anonymous
  • anonymous
You're welcome
triciaal
  • triciaal
|dw:1440384808581:dw|
triciaal
  • triciaal
|dw:1440385345310:dw|

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