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anonymous

  • one year ago

Need help with square root problem please :)

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  1. anonymous
    • one year ago
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    |dw:1440383921670:dw|

  2. anonymous
    • one year ago
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    sorry if you cant read this. but i multiped 7 and 5 and got 35 multiplied 2 and 6 and got the square root of 12 and i multiplied 7 and 4 and got -28 and i tried multiplying 7 and the square root of 2 but it gives me 14 and everytime i try to simplify it doesnt make sense and doesnt give me the right answer.

  3. anonymous
    • one year ago
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    the answer is 70 and square root of 3 -56 but how is it 56?

  4. anonymous
    • one year ago
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    \[70\sqrt{3}-56\] okay thats the answer

  5. anonymous
    • one year ago
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    Using the distributive property\[7\sqrt{2}\left( 5\sqrt{6}-4\sqrt{2} \right)\]\[=35\sqrt{12} - 28\sqrt{4}\]Does this help?

  6. anonymous
    • one year ago
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    but dont you multiply the 7 and the square root of 2?

  7. anonymous
    • one year ago
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    It helps, but im just wondering why i dont multiply it

  8. anonymous
    • one year ago
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    You're multiplying \(7\sqrt{2}\) by \(4\sqrt{2}\). You multiply the coefficients together and the radicals together to give \(28\sqrt{4}\) which, of course, can be simplified.

  9. anonymous
    • one year ago
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    oh! okay i understand!! thank you so much. :)

  10. anonymous
    • one year ago
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    In general\[a \sqrt{b} \times c \sqrt{d} = ac \sqrt{bd}\]

  11. anonymous
    • one year ago
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    You're welcome

  12. triciaal
    • one year ago
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    |dw:1440384808581:dw|

  13. triciaal
    • one year ago
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    |dw:1440385345310:dw|

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