"For problems 1 & 2, find the slope of the line passing through the given points." The points are (6,15) and (4,5) for the first problem. I don't want the answer, I want someone to walk me through it!

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"For problems 1 & 2, find the slope of the line passing through the given points." The points are (6,15) and (4,5) for the first problem. I don't want the answer, I want someone to walk me through it!

Algebra
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Alright. Does this formula sound familiar?
|dw:1440384901918:dw|
sorry I had to get on my laptop, but yes it does

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it's ok! alright.
|dw:1440385456076:dw| Does that make sense?
sorry for the bad handwriting lol
Yes it makes sense :)
I substituted those, i switched it to y1-y2 over x1-x2. I got 10 over 2 which simplifies to 5?
You can do that :) I learned it as y2-y1/x2-x1, but what you did is okay too :)
And you got the right slope! Good job :)
So is that all I would have to write for the answer, 5? Or do I have to do anything else? And The second problem is a little different, if you dont mind helping me with that after this :)
They're just asking about the slope, so that's it. I don't mind helping at all :)
Thank you! That was more simple than what I thought it'd be! And I will take a picture of number 2 with my phone, it's a graph
Sure! :)
This is the graph
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Don't mind the equation that was something I'd written a day or two ago
Is the first point (2,5)? I can't see it very well.
Honestly, i can barely see it! All I can make out is the (5, -1) /:
I think it's (2,5) xD It's the same process as the last question.
Just use the y1-y2/x1-x2 formula :)
For the second problem, I got the answer of -2
That's correct :)
Okay this is the last one, I swear. I havent done slope in two years. I have to do more problems and they're the ones I have trouble with - graphing. But for the problem 3, its "what is an equation of a line with slope 8 and y intercept 10?"
That's ok!
Thanks for your help btw!
Np! y=mx+b m is your slope, so now you've got y=8x+b b is your y-intercept, so plug in 10, and what do you get?
y=8x+10?
yep!
Thats it?
yep :)
it's a lot simpler than you think :o
It sure is. Its been so long since Ive done it, but now Im starting to remember it! thank you so much for your help :) i gave you a medal lol
I totally understand the feel, lol. And np! Thanks!! I'm around to help, so if you need anything else, just hmu!
Would I do the y1-y2 over X1-x2?
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that would get your slope. then you plug in one of those coordinates to get your y-intercept :o once you have your slope and y-intercept you have your equation
I got the slope of 4, is that right? And how do I get y intercept? y=mx+b , would I say y=4x+ A random coordinate?
that's the right slope.
|dw:1440388219466:dw|
i got it down to 3=12+b
Alright. What would b be then?
Would i subtract 3 from both sides? i'm bad at this. lol
subtract 12 from both sides
-9.. so the equation would be y=4x-9?
yep :)
thank you so much, Im about to go to bed haha! have a good night
np! good night!

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