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Jamierox4ev3r
 one year ago
@nnesha
Jamierox4ev3r
 one year ago
@nnesha

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Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4\(\Large\frac{x^{2}}{x^{2}4}\)  \(\Large\frac{x+1}{x+2}\) here is ur question

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.2Oml thank you xD

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4alright 1st) try to factor out the equation 2nd) find common denominator

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.2alright. So if I recall correctly, first we factor the bottom right? So it would look like this: \[\frac{ x ^{2} }{ (x2)(x+2) }\frac{ x+1 }{ x+2 }\]

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.2so to make a common denominator, would you just multiply by x2? :ooo so it would look like this: \(\huge\frac{x^{2}}{(x2)(x+2)}  \huge\frac{(x+1)(x2)}{(x+2)(x2)}\)

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.2if this is correct, I think I'm finally starting to get it O_O

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4yes right common denominator: (x2)(x+2)

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.2so that is a thing. oh my giblets. Ahh i forget. Now what do I do from here?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4now multiply numerator of 1st fraction by the denominator of 2nd fraction multiply numerator of 2nd fraction by the denominator of 1st fraction

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.2oh, so would you just cross multiply?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4yes but don't forget the sign

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.2ah yes, the subtraction sign. thanks bbg

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4\(\color{blue}{\text{Originally Posted by}}\) @Jamierox4ev3r so to make a common denominator, would you just multiply by x2? :ooo so it would look like this: \(\huge\frac{x^{2}}{(x2)(x+2)}  \huge\frac{(x+1)(x2)}{(x+2)(x2)}\) \(\color{blue}{\text{End of Quote}}\) ahh i see you already did that part

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.2oh wait. wasn't that a part of making it have a common denominator? XDD so NOW what do I do?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4\(\huge\frac{x^{2}}{(x2)(x+2)}  \huge\frac{(x+1)(x2)}{(x+2)(x2)}\) now you\[\huge\rm \frac{ x^2 \color{ReD}{(x2)(x+1)} }{( x2)(x+2)}\] can write the numerator under same denominator foil (x2)(x+1) and then distribute it by  sign

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.2ohhhh right, since the denominators are now common. makes sense :o so first foil, then distribute? If you foil (x2)(x+1), you get \(x^{2}x2\) and then if you distribute the negative sign, you get \(x^{2}+x+2\)

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.2So then you would have this: \(\huge\frac{x^{2}x^{2}+x+2}{(x+2)(x2)}\)

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.2alright. I know that x^2  x^2 = 0 , and x+2 over x+2 equals one. so your final answer, I believe, would be this: \(\huge\frac{1}{x2}\)

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.2OH MY GOD I GET IT

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.2you are my goddess ily

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.2seriously, thank you soo much. You deserve all 4 of those medals XD

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4just pray for me hahah medals aren't important :=)

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.2me? d'aww thank you so much. I do tend to have a strong understanding in math, but some of these topics are things that I've forgotten since I've done them so long ago. Kudos to you for being able to explain things so clearly.
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