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Jamierox4ev3r
 one year ago
Even more review!
5d. Simplify the following rational expression:
Jamierox4ev3r
 one year ago
Even more review! 5d. Simplify the following rational expression:

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Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.1\(\huge\frac{\frac{y}{x}\frac{x}{y}}{\frac{1}{y}\frac{1}{x}}\)

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.1^there's the expression. Any ideas? I'm not sure, but as a first step, perhaps you could multiply the numerator by the denominator in order to get rid of the denominator. Not sure, however.

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.1@Nnesha any ideas?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4i would find common denominator of top and bottom part

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4wait a sec let me show u wath i mean

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.1Okay..I'm still in the process of letting what you just told me sink in... so to find the common denominator, would you have to invert? and multiply?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4just multiply that's how i remember this if there is anything similar in the denominator just write one time here is an example \[\frac{ 1 }{ x}\frac{ z }{ x }\] both denominator are the same so just x is common denominator not x^2 another example \[\frac{ x }{ y }\frac{ z }{ x }\] both denominator are different so `multiply`them so for this question common denominator is xy

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4\[\frac{ y }{\color{reD}{ x} }\frac{ x }{\color{blue}{ y}}\] x and y aren't same so multiply them

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.1right, and that would give you \(xy\)

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.1So, the goal here is to make get common denominators in the top and bottom of this expression. oml let's try this thing out XD

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4yes right then you can change division to multiplication it will it make it easier

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.1SO I tried to do the thing. And this is what I ended up with. I'm not sure if it's right, but here it is anyway: \[\huge\frac{ \frac{ y^{2} }{ yx}  \frac{ x^{2} }{ yx } }{ \frac{ x }{ yx }  \frac{ y }{ yx }}\]

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.1is this right? >.<

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4\(\huge\color{green}{\checkmark}\)

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.1nice! and then you can combine it to have this: \[\huge\frac{ \frac{ y^{2}x^{2} }{ yx } }{ \frac{ xy }{ yx } }\]

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.1nice! now how do i get rid of the big ugly fraction bar? oo

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.1or what do i do next? :P

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4now multiply the top fraction by `reciprocal` of the bottom fraction i'll give you an example \[\huge\rm \frac{ \frac{ a }{ b } }{ \frac{ c }{ d }} =\frac{ a }{ b } \times \frac{ d }{ c }\]

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.1whoops i meant \(\huge\frac{y^{2}x^{2}}{yx}\times\huge\frac{yx}{xy}\)

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.1\(\huge\frac{y^{2}x^{2}}{\color{red}{yx}}\times\huge\frac{\color{red}{yx}}{xy}\) the stuff in red can be cancelled out i believe

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.1lol whoops you just said that XD lagggg

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4\[\rm y^2x^2\] can be written as x^2+y^2 factor out the negative one :=)

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.1wait. so you would have this: \(\huge\frac{x^{2}+y^{2}}{xy}\)

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.1is that right? oo

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.1oh. OML=OH MY LORD it's basically how i say "oh my god" (omg) lol :P

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.1so from here, what is the last step?

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.1\(\huge\frac{x^{2}+y^{2}}{xy}\) correct me if I'm wrong, but would i multiply the numerator by the denominator?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4\(\huge\frac{x^{2}+y^{2}}{xy}\) there is negative at front of x^2 factor it out

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4yes!! you can do that ttoo but still you must have to take out the negative one

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4\(\color{blue}{\text{Originally Posted by}}\) @Jamierox4ev3r \(\huge\frac{x^{2}+y^{2}}{xy}\) correct me if I'm wrong, but would i multiply the numerator by the denominator? \(\color{blue}{\text{End of Quote}}\) you would multiply the fraction with the `conjugate` of the denominator what is the conjugate of xy ?

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.1ookay. so when you say factor it out, it would look like \((x^{2}y^{2})\) and the conjugate of xy is x+y ^^

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.1nice nice! so we've got this then: \(\huge\frac{(x^{2}  y^{2})(x+y)}{xy (x+y)}\)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4\(\huge\color{green}{\checkmark}\)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4how did you eliminate the denominator ? or there is a typo ?;) eliminated by what ? :)

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.1wait...doesn't multiplying by the conjugate eliminate the denominator? ah geez I don't recall XD OH wait...if you multiply xy by x+y, don't you get \(x^{2}+xyxyy^{2}\) ? and then the +xy and xy cancel out, so you're left with \( x^{2} y^{2}\).

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4correct so there is a typo n the previous comment hmm let's see

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.1oh my gosh i don't know why i was talking about canceling so soon! I get it now And no there was no typo, i just didn't know what i was talking about lol :P so after doing the whole multiplication thing in the denominator, you have this: \(\huge\frac{(x^{2}y^{2})(x+y)}{x^{2}y^{2}}\)

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.1then, this should leave you with a final answer of \(\huge(x+y)\)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4yes! right! you can distribute parentheses by negative one

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.1yep, and you'd have xy :P oh my gosh i get it!

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4\(\huge\color{green}{\checkmark}\) :=) very nice!

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.1Thank you thank you! :33 Alright, it's getting kind of late. This is my last question of the night, but expect more tomorrow or sometime. Once again, thank you very much my lovely c': Have a nice day/evening/afternoon

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4my pleasure :=) gO_Od night!
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