## anonymous one year ago Identify the axis of symmetry and vertex of f(x) = –2x^2 –2x–1. A) Axis of symmetry: x = 0.5; Vertex: (0.5, – 0.50) B) Axis of symmetry: x = – 0.5; Vertex: (– 0.5, 0.50) C) Axis of symmetry: x = – 0.5; Vertex: (– 0.5, – 0.50) D) Axis of symmetry: x = 0.5; Vertex: (– 0.5, – 0.50)

1. Nnesha

here is the formula to find x-coordinate of vertex$\rm x=\frac{ -b }{ 2a }$ x coordinate of vertex= axis of symmetry

2. Nnesha

and then substitute all x's by its value into f(x) function to find y-coordinate of the vertex

3. Nnesha

need help ?