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anonymous
 one year ago
Identify the axis of symmetry and vertex of f(x) = –2x^2 –2x–1.
A) Axis of symmetry: x = 0.5; Vertex: (0.5, – 0.50)
B) Axis of symmetry: x = – 0.5; Vertex: (– 0.5, 0.50)
C) Axis of symmetry: x = – 0.5; Vertex: (– 0.5, – 0.50)
D) Axis of symmetry: x = 0.5; Vertex: (– 0.5, – 0.50)
anonymous
 one year ago
Identify the axis of symmetry and vertex of f(x) = –2x^2 –2x–1. A) Axis of symmetry: x = 0.5; Vertex: (0.5, – 0.50) B) Axis of symmetry: x = – 0.5; Vertex: (– 0.5, 0.50) C) Axis of symmetry: x = – 0.5; Vertex: (– 0.5, – 0.50) D) Axis of symmetry: x = 0.5; Vertex: (– 0.5, – 0.50)

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Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1here is the formula to find xcoordinate of vertex\[\rm x=\frac{ b }{ 2a }\] x coordinate of vertex= axis of symmetry

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1and then substitute all x's by its value into f(x) function to find ycoordinate of the vertex
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