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anonymous
 one year ago
Help solving cos^2 (2x) sin^2 (2x)=0 and sin(2x)=sin x ?
anonymous
 one year ago
Help solving cos^2 (2x) sin^2 (2x)=0 and sin(2x)=sin x ?

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arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1Do you have options? i guess I found the first answer... but need to check if it matches @Kiritina

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0cos^2 (2x) sin^2 (2x) = cos(4x)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No answers available, sorry. I'm not sure where to start with either equation.

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1can you manage now @Kiritina or should i do the solution?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'd love it if you helped with the solution!

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.0lets see... \[\cos^2(2x) \sin^2(2x) = 0\]\[\color{red}{\sin(2x) = \sin(x)}\] is the red portion what you're given? Do you mind posting the actual problem by a picture?

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1O yes @Jhannybean is right I just solved the black portion I didn't think about the red!

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1ok both are different problems hehe :D

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.0So you're looking for a general solution... x_x I'm terrible at finding those.

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1okay 1st question we have cos^2xsin^2x=0 =>cos4x=0 \[=>4x=\cos^{1} (0)\] \[=\cos^{1} (\cos (\frac{ \pi }{ 2}))\] =>4x=pi/2 >x=pi/8

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.12nd question, sin2x=2sinxcosx so, sin2x=sinx =>2sinxcox/sinx=1 =>2cosx=1 =>cosx=1/2 x=cos inverse(1/2) x=cos inverse (cos pi/3) x=pi/3

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1@Kiritina if you liked my response, dont forget to medal and fan. Thank you
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