anonymous
  • anonymous
FAN AND MEDAL
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Identify square root of 2 as either rational or irrational, and approximate to the tenths place. Rational: square root of 2 ≈ 1.5 Irrational: square root of 2 ≈ 1.5 Rational: square root of 2 ≈ 1.4 Irrational: square root of 2 ≈ 1.4
anonymous
  • anonymous
@isaac4321
SolomonZelman
  • SolomonZelman
Ok, do you knwo what RATIONAL and IRRATIONAL numbers are?

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SolomonZelman
  • SolomonZelman
let me briefly introduce all numbers to you, ok?
anonymous
  • anonymous
ok
anonymous
  • anonymous
i think the answer is D
anonymous
  • anonymous
hey @kiamousekia
anonymous
  • anonymous
hey
anonymous
  • anonymous
you are right
SolomonZelman
  • SolomonZelman
`Natural numbers:` \(\color{black}{ \displaystyle 1,~~2,~~3,~~4,~~5,~~6~~... }\) `Whole numbers:` \(\color{black}{ \displaystyle 0,~~1,~~2,~~3,~~4,~~5,~~6~~... }\) (same as natural numbers, BUT INCLUDES ZERO) `Integers:` \(\color{black}{ \displaystyle ...~-6,~~-5,~~-4,~~-3,~~-2,~~-1,~~0~~1,~~2,~~3,~~4,~~5,~~6~~... }\) (positive and negative whole numbers) `Rational numbers:` Fractions, like \(\color{black}{ \displaystyle 1/5,~ }\) \(\color{black}{ \displaystyle -4/9,~~~~10/7 }\) and on Also, \(\color{black}{ \displaystyle \sqrt{16} }\) since it is really a 4) and all roots, if and only if the number inside is a perfect square (perfect cube or whatever) (But Rational numbers also includes all integers) `Irrational number` Roots like, \(\color{black}{ \displaystyle \sqrt{3},~~\sqrt[8]{8} }\) Also Euler (and other) special constants such \(\color{black}{ \displaystyle \pi,~e,~\psi~ }\) Also logarithms \(\color{black}{ \displaystyle \ln(2) }\), \(\color{black}{ \displaystyle \log_9{7} }\) ...
anonymous
  • anonymous
by the way d is the answer
anonymous
  • anonymous
thanks
anonymous
  • anonymous
i will give the medal and fan to @SolomonZelman because he/she sorry but i don't... because he/she used a lot of time to try to help me
SolomonZelman
  • SolomonZelman
You don't have to, i got enough meds and fans o~o As long as you have all of the knowledge that you were looking for ....
SolomonZelman
  • SolomonZelman
(not that i mind though)
anonymous
  • anonymous
okay but thanks for helping
SolomonZelman
  • SolomonZelman
You welcome~!
anonymous
  • anonymous
i don't know you
anonymous
  • anonymous
k

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