FAN AND MEDAL

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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Identify square root of 2 as either rational or irrational, and approximate to the tenths place. Rational: square root of 2 ≈ 1.5 Irrational: square root of 2 ≈ 1.5 Rational: square root of 2 ≈ 1.4 Irrational: square root of 2 ≈ 1.4
Ok, do you knwo what RATIONAL and IRRATIONAL numbers are?

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let me briefly introduce all numbers to you, ok?
ok
i think the answer is D
hey
you are right
`Natural numbers:` \(\color{black}{ \displaystyle 1,~~2,~~3,~~4,~~5,~~6~~... }\) `Whole numbers:` \(\color{black}{ \displaystyle 0,~~1,~~2,~~3,~~4,~~5,~~6~~... }\) (same as natural numbers, BUT INCLUDES ZERO) `Integers:` \(\color{black}{ \displaystyle ...~-6,~~-5,~~-4,~~-3,~~-2,~~-1,~~0~~1,~~2,~~3,~~4,~~5,~~6~~... }\) (positive and negative whole numbers) `Rational numbers:` Fractions, like \(\color{black}{ \displaystyle 1/5,~ }\) \(\color{black}{ \displaystyle -4/9,~~~~10/7 }\) and on Also, \(\color{black}{ \displaystyle \sqrt{16} }\) since it is really a 4) and all roots, if and only if the number inside is a perfect square (perfect cube or whatever) (But Rational numbers also includes all integers) `Irrational number` Roots like, \(\color{black}{ \displaystyle \sqrt{3},~~\sqrt[8]{8} }\) Also Euler (and other) special constants such \(\color{black}{ \displaystyle \pi,~e,~\psi~ }\) Also logarithms \(\color{black}{ \displaystyle \ln(2) }\), \(\color{black}{ \displaystyle \log_9{7} }\) ...
by the way d is the answer
thanks
i will give the medal and fan to @SolomonZelman because he/she sorry but i don't... because he/she used a lot of time to try to help me
You don't have to, i got enough meds and fans o~o As long as you have all of the knowledge that you were looking for ....
(not that i mind though)
okay but thanks for helping
You welcome~!
i don't know you
k

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