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|dw:1440432029210:dw|
\(\large \color{black}{\begin{align} & \normalsize \text{In how many ways can u place the given colored circles in a circle}\hspace{.33em}\\~\\ \end{align}}\)
I don't quite get the Q-:( In how many ways you can place them `in a circle`?

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Other answers:

yes this one ^
i still don't understand what they mean by placing these squares into a circle. Can someone explain to me what is exactly happening?
example assume the colored circles are objects \(\large \color{black}{\begin{align} &\normalsize \text{in how many ways can u place the objects in a circle} \hspace{.33em}\\~\\ \end{align}}\)
do u understand now ?
All I can tell you is that if you rearrange them in different order, then the number of these rearrangements is going to be equivalent to: \(\large\color{black}{ \displaystyle 8{\rm P}8=\frac{8!}{(8-8)!} =40320 }\) But I am not sure how much that relates to the question, because I still don't actually understand the case in the question.
but did u understand the question
imquerty did u understand the question
|dw:1440433304680:dw|
|dw:1440433349497:dw|
is the answer \(8!\)
it is given 7!
so i was right then? you are asking about the number of all possible permutations of these objets
wait, you are saying now the answer is actually 7!, (not 8!) ?
book says 7!
Maybe you are placing 7 of these circles, into the remaining circle, and want to find the number of the permutations of the 7 circles' placement into that remaining circle?
becuase I don't really see how 8P8 can be equal to 7! must be we missed the correct interpretation of the Q
Are these two considered same ? |dw:1440434077044:dw| |dw:1440434088056:dw|
yes i think
found this http://mathworld.wolfram.com/CircularPermutation.html
ok, fits:)

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