anonymous
  • anonymous
could someone give me assistance with this question/
Mathematics
  • Stacey Warren - Expert brainly.com
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schrodinger
  • schrodinger
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anonymous
  • anonymous
The asymptote of the function f(x) = 3x + 4 is y =
e.mccormick
  • e.mccormick
Well, an asymptote is a line it does not cross. Is there any line that does not cross?
e.mccormick
  • e.mccormick
Well... vertical ones it does not cross. Here is a better definition: https://www.mathsisfun.com/algebra/asymptote.html

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Nnesha
  • Nnesha
I guess you have to find horizontal asy. for \(\color{green}{\rm Vertical~ asy.}\) set the denominator equal to zero and then solve for the variable. for\(\color{green}{\rm Horizontal ~asy.}\) focus on highest degrees ~if the highest degree of the numerator is greater than the denominator then `No horizontal asy.` \[\color{reD}{\rm N}>\color{blue}{\rm D}\] example \[\large\rm \frac{ 7x^\color{ReD}{3} +1}{ 4x^\color{blue}{2}+3 }\] ~if the highest degree of the denominator is greater than the highest degree of the numerator then `y=0` would be horizontal asy. \[\rm \color{reD}{N}<\color{blue}{\rm D}\] example:\[\large\rm \frac{ 7x^\color{red}{2}+1 }{ 4x^\color{blue}{3}+3 }\] ~if both degrees are the same then divide the leading coefficient of the numerator by the leading coefficient of the denominator \[\rm \color{red}{N}=\color{blue}{D}\] \[\large\rm \frac{ 8x^\color{reD}{3}+1 }{ 4x^\color{blue}{3}+3 }\] \[\rm \frac{ 8x^3 }{ 4x^3 } =2\] horizontal asy. =2
Nnesha
  • Nnesha
Slant asy when the highest degree of the denominator is one less than the highest degree of the numerator. don't know about oblique i guess slant and oblique both are the same hmmm? not sure
e.mccormick
  • e.mccormick
Yes, oblique and slant are the same. But what he gave was a line... so not sure what would apply.
Nnesha
  • Nnesha
ohh cool. thanks

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