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anonymous

  • one year ago

could someone give me assistance with this question/

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  1. anonymous
    • one year ago
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    The asymptote of the function f(x) = 3x + 4 is y =

  2. e.mccormick
    • one year ago
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    Well, an asymptote is a line it does not cross. Is there any line that does not cross?

  3. e.mccormick
    • one year ago
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    Well... vertical ones it does not cross. Here is a better definition: https://www.mathsisfun.com/algebra/asymptote.html

  4. Nnesha
    • one year ago
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    I guess you have to find horizontal asy. for \(\color{green}{\rm Vertical~ asy.}\) set the denominator equal to zero and then solve for the variable. for\(\color{green}{\rm Horizontal ~asy.}\) focus on highest degrees ~if the highest degree of the numerator is greater than the denominator then `No horizontal asy.` \[\color{reD}{\rm N}>\color{blue}{\rm D}\] example \[\large\rm \frac{ 7x^\color{ReD}{3} +1}{ 4x^\color{blue}{2}+3 }\] ~if the highest degree of the denominator is greater than the highest degree of the numerator then `y=0` would be horizontal asy. \[\rm \color{reD}{N}<\color{blue}{\rm D}\] example:\[\large\rm \frac{ 7x^\color{red}{2}+1 }{ 4x^\color{blue}{3}+3 }\] ~if both degrees are the same then divide the leading coefficient of the numerator by the leading coefficient of the denominator \[\rm \color{red}{N}=\color{blue}{D}\] \[\large\rm \frac{ 8x^\color{reD}{3}+1 }{ 4x^\color{blue}{3}+3 }\] \[\rm \frac{ 8x^3 }{ 4x^3 } =2\] horizontal asy. =2

  5. Nnesha
    • one year ago
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    Slant asy when the highest degree of the denominator is one less than the highest degree of the numerator. don't know about oblique i guess slant and oblique both are the same hmmm? not sure

  6. e.mccormick
    • one year ago
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    Yes, oblique and slant are the same. But what he gave was a line... so not sure what would apply.

  7. Nnesha
    • one year ago
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    ohh cool. thanks

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