I have been told that two roots of the equation x^4 - 5x^2+2x=0 are 0 and -2. It then asks me to find the two other roots. The method I have been given tells me to use the constant and check all the factors of the constant with the equation to find the roots. Since there is no constant, will you please help me find what to do?
Stacey Warren - Expert brainly.com
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if the roots are a and b then (x-a) and (x-b) are factors of the polynomial.
the highest exponent of the variable is 4 so there are 4 roots.
f(x) = (x-a)(x-b)(x-c)(x-d) roots a, b, c, d
f(x) divided by (x-a)(x-b) = (x-c)(x-d)
can you see f(x)/x(x+2) = a quadratic to be factored ?
when you factor that quadratic set = 0 solve to get the other roots
sorry I am blanking out
what happens when you divide by x^2 + 2 ?
Oh! I havnt done that yet! Sorry let me try that now
you divide the quotient by x
your constant was 8 factors of 8 are ?
did not check your division remainder needed for "quadratic"
the remainder theorem says if (x-a) is a factor then there is no remainder when you compute f(a)
Yes, I know that. I just dont understand how to get the other two roots. When trying to figure out how to do it myself I looked at the answers (back of my text book) and it said the answers were -1 and plus or minus the square root of 2. How do I get to those answers? Would it be better if I sent a picture of the questions from the actual book?
sorry I can't explain it better right now
when I divide f(x) by x^2 had to add 1 to complete the quadratic so x-1 is a factor
Quotient x^2 - 4 the factors are (x+2)(x-2)
I guess from the method you need to use
the remainder you have is -8 and one root is -2 so the other 4
Ok, thanks very much for your help, unfortunately I still dont understand but maybe its because where I am its quite late so I will look at it again in the morning when you brain is fresh :). Thank you very much though