Which of the following is the correct graph of the compound inequality 4p + 1 > −11 or 6p + 3 < 39? a number line with closed circles at negative 3 and 6 and shading in between. number line with open dot at negative 3 with shading to the left and an open dot at 6 with shading to the right. number line with open dots at negative 2 and 5 with shading in between. number line with shading everywhere.

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Which of the following is the correct graph of the compound inequality 4p + 1 > −11 or 6p + 3 < 39? a number line with closed circles at negative 3 and 6 and shading in between. number line with open dot at negative 3 with shading to the left and an open dot at 6 with shading to the right. number line with open dots at negative 2 and 5 with shading in between. number line with shading everywhere.

Mathematics
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Help?!?!
ok so you want to leave p one one side of the inequality so how would you do that for: 4p + 1 > -11

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Other answers:

divide -11 by 1 so 4p<1?
no, you would do: 4p + 1 > -11 4p + 1 -1 > -11 -1 4p > -12 4p/4 > -12/4 p > -3 do you understand?
yes
ok now try doing the same thing I did for: 6p + 3 < 39
in steps like I did above
6p + 3 < 39 6p+3-3<39-3 6p<42 p>7
ok so what is 39 -3 ?
36
yes so try to fix your mistake above
oh 6p<36 p>6
ok so here you don't switch the sign because you are not dividing the number by a negative number so the answer would be: p < 6 does that make sense?
okay thk lots
no problem :)

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