Can someone please help me step by step with this problem? x^(-2/3) (2-x)^2 - 6x^1/3 (2-x)

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Can someone please help me step by step with this problem? x^(-2/3) (2-x)^2 - 6x^1/3 (2-x)

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Without knowing exactly what you're trying to do, we can't help much. I'd guess you're wanting to simplify the given expression. \[x^{-2/3}(2-x)^2-6x^{1/3}(2-x)\] For starters, there's a common factor of \(2-x\), so let's pull that out: \[(2-x)\left[x^{-2/3}(2-x)-6x^{1/3}\right]\] Next, notice that \(-\dfrac{2}{3}=-\dfrac{3}{3}+\dfrac{1}{3}\). Since \(x^{a+b}=x^ax^b\), this means that \(x^{-2/3}=x^{-3/3}x^{1/3}=x^{-1}x^{1/3}\), and so the two bracketed terms share another common factor of \(x^{1/3}\). Pulling that out gives \[x^{1/3}(2-x)\left[x^{-1}(2-x)-6\right]\] What else can you do?

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