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rainbow_rocks03

  • one year ago

PLZ HELP NO DIRECT ANSWERS...will medal+fan. Which is equivalent to the expression shown when a>0 and b>0?

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  1. rainbow_rocks03
    • one year ago
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    |dw:1440439527592:dw|

  2. rainbow_rocks03
    • one year ago
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    |dw:1440439634803:dw|

  3. ikram002p
    • one year ago
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    what have u tried ?

  4. rainbow_rocks03
    • one year ago
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    i dont understand this

  5. ikram002p
    • one year ago
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    ok :) so basically u can delete common terms in numerator and denominator according to this statement \(\Large \dfrac{a}{a}=1 \)

  6. rainbow_rocks03
    • one year ago
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    ok

  7. ikram002p
    • one year ago
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    so what can u cancel from this ?|dw:1440440526567:dw|

  8. ikram002p
    • one year ago
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    for example |dw:1440440587931:dw|

  9. ikram002p
    • one year ago
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    what else can u cancel to make in the simplest form ?

  10. rainbow_rocks03
    • one year ago
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    the a's

  11. ikram002p
    • one year ago
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    yes one of them note that \(\Large a^2=a.a\)

  12. ikram002p
    • one year ago
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    |dw:1440440792739:dw| now whats left ?

  13. ikram002p
    • one year ago
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    PS : 21=3*7 & 35=5*7

  14. rainbow_rocks03
    • one year ago
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    3*7=21 & 5*7=35

  15. rainbow_rocks03
    • one year ago
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    so my answer would be d? @ikram002p

  16. SolomonZelman
    • one year ago
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    I don't think you need to know that \(\color{blue}{\left\{a,~b\right\}>0}\).

  17. rainbow_rocks03
    • one year ago
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    @ikram002p ?

  18. ikram002p
    • one year ago
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    don't forget the minus sign `-`

  19. rainbow_rocks03
    • one year ago
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    oh so my answer would be c

  20. SolomonZelman
    • one year ago
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    Don't really know why the posted it, if b/b and a/a is 1 for any a even if was \(i\cdot \psi \cdot e \cdot \pi\)

  21. ikram002p
    • one year ago
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    we have canceled b from numerator

  22. ikram002p
    • one year ago
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    @SolomonZelman she need to know since a^2=a.a :D to be more accurate about the answer

  23. SolomonZelman
    • one year ago
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    a•a you mean by a.a ?

  24. SolomonZelman
    • one year ago
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    \(\large\color{black}{ \displaystyle \frac{ -21a^2b }{35ab} =\frac{(-3)\cdot7\cdot a \cdot a \cdot b}{5 \cdot 7\cdot a \cdot b} =\frac{(-3)\cdot a}{b}\times \frac{7\cdot a \cdot b}{7\cdot a \cdot b}}\) i haven't crossed any numbers out, all I did so far is a rearrangement that is valid \(\forall~~a,b\) (for all a and b)

  25. ikram002p
    • one year ago
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    yes which looks more nice :)

  26. SolomonZelman
    • one year ago
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    Thanks:) I mean even if there is any point in making a>0, though in by "b" we would never need such a condition.

  27. SolomonZelman
    • one year ago
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    oh, they should have said b and a are not 0, tho' ....

  28. SolomonZelman
    • one year ago
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    ok, now you know that because they said a and b >0. So Blank/Blank = 1, right?

  29. SolomonZelman
    • one year ago
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    u left with. ....

  30. ikram002p
    • one year ago
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    i agree with u but OP seems left :P

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