Solve the following expression for x: 81=3(x+y)^3 x = 243 - y x = 27 - y x = 3 - y x = 9 - y

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Solve the following expression for x: 81=3(x+y)^3 x = 243 - y x = 27 - y x = 3 - y x = 9 - y

Mathematics
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\(81=3(x+y)^3\) Divide both sides by 3. What do you get?
27
what three am i taking away on the side though the exponent or the first 3
hint: we can write this: \[\Large {\left( {x + y} \right)^3} = \frac{{81}}{3} = 27\]
ok then how do i get rid of the exponent
you have to take the third rooth of both sides
so how would i do that?
how do you takw the 3 root of both sides
Correct. \(27=(x+y)^3\) Now we notice that \(27 = 3^3\), so we write: \(3^3 = (x + y)^3\) If the third power of 3 equals the third power of x + y, then 3 must equal x + y. You can also take the cubic root of both sides. \(3 = x + y\) There is only one step left. Subtract y from both sides.
so would it be 3-y=x @Michele_Laino or 9-y= x
it is the first one, namely x+y=3
ok
The following equation is used to determine the kinetic energy of an object: E=1/2mv^2. Solve for m:
would it be 2E/ v^2
correct!
Thank you
Write an expression for the following description: 23 less than the product of x and 6. 6x-23 is that right
yes!

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