18jonea
  • 18jonea
Solve the following expression for x: 81=3(x+y)^3 x = 243 - y x = 27 - y x = 3 - y x = 9 - y
Mathematics
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SOLVED
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schrodinger
  • schrodinger
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18jonea
  • 18jonea
@Michele_Laino
18jonea
  • 18jonea
@Miracrown
anonymous
  • anonymous
Ill try to help you but I'm not gonna put a answer if i think I'm wrong

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More answers

mathstudent55
  • mathstudent55
\(81=3(x+y)^3\) Divide both sides by 3. What do you get?
18jonea
  • 18jonea
27
18jonea
  • 18jonea
what three am i taking away on the side though the exponent or the first 3
18jonea
  • 18jonea
@mathstudent55
18jonea
  • 18jonea
@Michele_Laino
Michele_Laino
  • Michele_Laino
hint: we can write this: \[\Large {\left( {x + y} \right)^3} = \frac{{81}}{3} = 27\]
18jonea
  • 18jonea
ok then how do i get rid of the exponent
Michele_Laino
  • Michele_Laino
you have to take the third rooth of both sides
18jonea
  • 18jonea
so how would i do that?
18jonea
  • 18jonea
how do you takw the 3 root of both sides
mathstudent55
  • mathstudent55
Correct. \(27=(x+y)^3\) Now we notice that \(27 = 3^3\), so we write: \(3^3 = (x + y)^3\) If the third power of 3 equals the third power of x + y, then 3 must equal x + y. You can also take the cubic root of both sides. \(3 = x + y\) There is only one step left. Subtract y from both sides.
18jonea
  • 18jonea
so would it be 3-y=x @Michele_Laino or 9-y= x
Michele_Laino
  • Michele_Laino
it is the first one, namely x+y=3
18jonea
  • 18jonea
ok
18jonea
  • 18jonea
The following equation is used to determine the kinetic energy of an object: E=1/2mv^2. Solve for m:
18jonea
  • 18jonea
@Michele_Laino
18jonea
  • 18jonea
would it be 2E/ v^2
18jonea
  • 18jonea
@mathstudent55
Michele_Laino
  • Michele_Laino
correct!
18jonea
  • 18jonea
Thank you
18jonea
  • 18jonea
Write an expression for the following description: 23 less than the product of x and 6. 6x-23 is that right
18jonea
  • 18jonea
@Michele_Laino
Michele_Laino
  • Michele_Laino
yes!

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