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Well, if x=0, then all the terms but the last go by by. So 0,3 must be on the graph.
THat alone eliminates everything other than A and D. So all you need to do is pick one other easy test point and you can confirm.
I would try x=1, cause then you do not really need to figure out much, and presto, second y value to check. With many of these types of questions, that is all you need to do. Find x=0 and x=1. It generally eliminates most of the graphs.
how would you do x=1? would you just substitute 1 in for all the x's and then solve it?
Yep. So you just end up with the numbers.
When x=0, every factor with an x dissapears. That is why x=0 is easy. For x=1, the x does not matter and you just add and subtract the constants.
And I am assuming you typoed the 9^2 and it is supposed to be 9x^2.
it just shows as 9^2 not 9x^2
Hmmm... that is probably a mistake, because NONE of the graphs are for it with 9^2 = 81. But one of them is for it with 9x^2.
yeah, i think it was a mistake. i just checked again and got A as my final answer, is this correct?
Yes. Cause when x=1 it would be 13. If yo look at (0,3) and (1,13) thy would only show up on graph A.
thank you so much! :)
np. Have fun, and no you know an easy way to do those. =)