anonymous
  • anonymous
Please help!!!!! MEDAL AND FAN!!!!!
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
Picture below
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anonymous
  • anonymous
anonymous
  • anonymous
I know for sure that it is not a rotation.

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anonymous
  • anonymous
So is it a translation?
mathmate
  • mathmate
If the image is the opposite hand of the preimage, then there is at least one reflection. Translations and rotations do not change "hands".
anonymous
  • anonymous
Oh yah you're right. Thx a bunch
mathmate
  • mathmate
So are you able to find the axis for the reflection?
mathmate
  • mathmate
You're welcome! :)

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