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ok so we lsit the ways to do this can you think of any

Yes, it does help!

So we first seat the 4 men, so there are 4! ways of seating the gents.
|dw:1440446507784:dw|

yep that pic explains it perfectly

ill give u another question similiar to this , try to figure it out :)

I'll try! lol

what if the 4 men and 3 women are seated around a round table

with the same constraint?

yes

lemme see.

0 ways

haha

ya

It's cheaper!

is 0 correct

ya its impossible ofcourse lol

yay!

|dw:1440447006885:dw|

|dw:1440446969033:dw|
So for the four men, there are 3! ways (rotational symmetry)

For the women, there are only 4 seats, so 4P3.
Now we multiply them together!

For some reason, men have to fight for women! lol

remember its not 4 men and 4 women mathmate,

yes^ i was wondering that pic

Four seat, but not all filled!

First women gets to choose from 4, then 3, then 2.

*woman

One seat will be empty, so remove the chair and two men will sit next to each other.

yep

here is a more involved question

Woah, not too difficult, I hope!

Is this a trick question? They seem like the ones we did.

no this one is more straightforward but theres some nice ways to do it efficiently

ill leave u the answers see if u get them both

4!5P4 for the first one,
and
3!4P4 for the second.

part a =1152
part b= 72

So I got them both wrong! lol

for first question of round table is this possible|dw:1440447723500:dw|

oh oops ya, i thought the question said no 2 women and no 2 wmen can sit together

i refuted my answer lol

no i wanted it to be like that, no gender together xD

oh it is different

yep thats right

ill check your first question answer in the mean time

u r close

remember that now since its m and w on a round table
mwmwmw = wmwmwm

so its not 1152/8
but 1152/2/8

Oh, for the straight row, I have 1152=2*4!4!
But for the round table, I still have 144=3!4!

well the way i connected the first answer to the 2nd is

u see how its 2*4!*4! theres no need for the 2 * anymore in the 2nd case since

w1m1w2m2 = m1w1m2w2
if u connect the edges
its the same arrangement

w1m1w2m2
for example this is equal to
m2w1m1w2

|dw:1440448675569:dw|

yep :)

do u get it too mathmath333

Sorry, @mathmath333, we hijacked your post! :(

hehe

was offline ,lol

Sorry mm333, we were discussing extensions to your problem! lol