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Candy13106
 one year ago
can someone help me pls
Candy13106
 one year ago
can someone help me pls

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Candy13106
 one year ago
Best ResponseYou've already chosen the best response.0ok wait ill finish the question

Candy13106
 one year ago
Best ResponseYou've already chosen the best response.0e bisects df with a line over it, de =2y and ef=8y3 find de ef and df

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0since E bisects DF, DE is equal to EF, so 2y = 8y3 solve for y 3=6y .5 = y so both DE and EF = 1 DF = DE + EF = 2 or if E bisects DF, that means DE = EF. Therefore, 2y = 8y  3 3 = 6y y = 0.5 DE = 1 EF = 1 DF = 2

Candy13106
 one year ago
Best ResponseYou've already chosen the best response.0yea. During a football game, a quarterback standing at the 9yard line passes the ball to a receiver at the 24yard line. The receiver then runs with the ball halfway to the 50yard line. How many total yards (passing plus running) did the team gain on the play?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0From the 9 yrd. line to the 24 yard line is 15 yards. Then it says he ran the ball HALFWAY to the 50 yard line. So he didn't quite make it to the 50 yard line. SO: 5024 = 26.. so 26 yards is the total distance from the 24 yard line to the 50 yard line. But.. he only ran half of it. So 26/2 = 13. So.. 15 + 13 = 28 yards total gained on the play.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah is that it if not just tag me :)
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