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Candy13106

  • one year ago

can someone help me pls

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  1. Candy13106
    • one year ago
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    E bisects

  2. anonymous
    • one year ago
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    sure I will try :)

  3. Candy13106
    • one year ago
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    ok wait ill finish the question

  4. Candy13106
    • one year ago
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    e bisects df with a line over it, de =2y and ef=8y-3 find de ef and df

  5. anonymous
    • one year ago
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    since E bisects DF, DE is equal to EF, so 2y = 8y-3 solve for y 3=6y .5 = y so both DE and EF = 1 DF = DE + EF = 2 or if E bisects DF, that means DE = EF. Therefore, 2y = 8y - 3 3 = 6y y = 0.5 DE = 1 EF = 1 DF = 2

  6. Candy13106
    • one year ago
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    ok thanks

  7. anonymous
    • one year ago
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    sure :)

  8. anonymous
    • one year ago
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    any other question

  9. Candy13106
    • one year ago
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    yea. During a football game, a quarterback standing at the 9-yard line passes the ball to a receiver at the 24-yard line. The receiver then runs with the ball halfway to the 50-yard line. How many total yards (passing plus running) did the team gain on the play?

  10. anonymous
    • one year ago
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    From the 9 yrd. line to the 24 yard line is 15 yards. Then it says he ran the ball HALFWAY to the 50 yard line. So he didn't quite make it to the 50 yard line. SO: 50-24 = 26.. so 26 yards is the total distance from the 24 yard line to the 50 yard line. But.. he only ran half of it. So 26/2 = 13. So.. 15 + 13 = 28 yards total gained on the play.

  11. Candy13106
    • one year ago
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    thanks again

  12. anonymous
    • one year ago
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    yeah is that it if not just tag me :)

  13. Candy13106
    • one year ago
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    ok

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