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JacksonJRB
 one year ago
Solve for x in terms of y.
y=x^24x+3
JacksonJRB
 one year ago
Solve for x in terms of y. y=x^24x+3

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SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1ok, I will show a similar problem.

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1\(\large\color{black}{ \displaystyle y=2x^23x+5 }\) \(\large\color{black}{ \displaystyle 0=2x^23x+5y }\) so a=2 b=3 c=(5y) \(\large\color{black}{ \displaystyle x=\frac{(3)\pm\sqrt{(3)^24(2)(5y)}}{2(2)} }\) \(\large\color{black}{ \displaystyle x=\frac{3\pm\sqrt{98(5y)}}{4} }\) \(\large\color{black}{ \displaystyle x=\frac{3\pm\sqrt{940+8y}}{4} }\) \(\large\color{black}{ \displaystyle x=\frac{3\pm\sqrt{31+8y}}{4} }\)

JacksonJRB
 one year ago
Best ResponseYou've already chosen the best response.1So, i just use quadratic formula?

JacksonJRB
 one year ago
Best ResponseYou've already chosen the best response.1Okay, I'll try it. Thanks

JacksonJRB
 one year ago
Best ResponseYou've already chosen the best response.1\[x=\frac{ 4+/ \sqrt{4+4y} }{ 2 }\]

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1let me check ...

JacksonJRB
 one year ago
Best ResponseYou've already chosen the best response.1\[x=2+/\sqrt{1+y}\]

JacksonJRB
 one year ago
Best ResponseYou've already chosen the best response.1Simplifies to that I believe

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1y=x^24x+3 0=x^24x+3y \(\large\color{black}{ \displaystyle x=\frac{4\pm\sqrt{(4)^24(1)(3y)}}{2} }\) \(\large\color{black}{ \displaystyle x=\frac{4\pm\sqrt{164(3y)}}{2} }\) \(\large\color{black}{ \displaystyle x=\frac{4\pm\sqrt{4(4(3y))}}{2} }\) \(\large\color{black}{ \displaystyle x=\frac{4\pm2\sqrt{4(3y)}}{2} }\) \(\large\color{black}{ \displaystyle x=2\pm\sqrt{4(3y)} }\) \(\large\color{black}{ \displaystyle x=2\pm\sqrt{43+y} }\) \(\large\color{black}{ \displaystyle x=2\pm\sqrt{1+y} }\) Very Nice!

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1Good job, keep that up:)

JacksonJRB
 one year ago
Best ResponseYou've already chosen the best response.1Thanks for the help

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1you have done it all yourself, i just pointed:)

JacksonJRB
 one year ago
Best ResponseYou've already chosen the best response.1There's another problem that involves fractions though

JacksonJRB
 one year ago
Best ResponseYou've already chosen the best response.1\[y=\frac{ x^2+1 }{ x^21 }\]

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1you want x in terms of y?

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1\(\large\color{black}{ \displaystyle y=\frac{x^2+1}{x^21} }\) \(\large\color{black}{ \displaystyle y=\frac{x^21+2}{x^21} }\) \(\large\color{black}{ \displaystyle y=\frac{x^21}{x^21}+\frac{2}{x^21} }\) \(\large\color{black}{ \displaystyle y=1+\frac{2}{x^21} }\) can you get it from there?

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1I didn't, I rewrote 1 as 21

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.11+2, is same as 1

JacksonJRB
 one year ago
Best ResponseYou've already chosen the best response.1I think I can finish it

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1ok, go ahead, but take your time...

JacksonJRB
 one year ago
Best ResponseYou've already chosen the best response.1\[x=\sqrt{\frac{ 2 }{ y1 }+1}\]

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1yes (I think though you need the \(\pm\) there)

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1But, I mean without the \(\pm\) you have still achieved the task. You solved for x in terms of y. You might not need ± because ()² or (+)² is all 1.
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