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JacksonJRB
 one year ago
Solve for x in terms of y. Please help!
JacksonJRB
 one year ago
Solve for x in terms of y. Please help!

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JacksonJRB
 one year ago
Best ResponseYou've already chosen the best response.0\[y=\sqrt{\frac{ 4x1 }{ x }}\]

JacksonJRB
 one year ago
Best ResponseYou've already chosen the best response.0Every new problem I look at seems to make less and less sense.

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1\(\large\color{black}{ \displaystyle y^2=\frac{4x1}{x} }\) \(\large\color{black}{ \displaystyle y^2=\frac{4x}{x}\frac{1}{x} }\) \(\large\color{black}{ \displaystyle y^2=4\frac{1}{x} }\) can you take it from there?

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1all they are asking you to do, is to isolate the x (without performing incorrect operations).

JacksonJRB
 one year ago
Best ResponseYou've already chosen the best response.0\[x=\frac{ 1 }{ y^24 }\]

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1yes, and if you want you can simplify that just a bit, to get: \(\large\color{black}{ \displaystyle x=\frac{1}{4y^2} }\)

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1You are always welcome

JacksonJRB
 one year ago
Best ResponseYou've already chosen the best response.0There is another one that I will try on my own for now but I'll ask if I need help again

JacksonJRB
 one year ago
Best ResponseYou've already chosen the best response.0\[y=\frac{ 1 }{ x^2+2x }\] \[x^2+2x=\frac{ 1 }{ y }\]

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1the second equation is the next step that you took?

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1Ok, you can subtract 1/y from both sides, and do the quadratic formula. a=1 b=2 c=1/y

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1\(\large\color{black}{ \displaystyle x^2+2x\color{red}{\frac{1}{y}}=\frac{1}{y}\color{red}{\frac{1}{y}} }\) \(\large\color{black}{ \displaystyle x^2+2x\frac{1}{y}=0 }\)

JacksonJRB
 one year ago
Best ResponseYou've already chosen the best response.0\[x=\frac{ 2+/\sqrt{4+\frac{ 4 }{ y }} }{ }\]

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1you can do a \(\pm\) sign in latex by \pm (just a code advise) and yes, so far correct

JacksonJRB
 one year ago
Best ResponseYou've already chosen the best response.0\[x=2\pm \sqrt{4y+4}\]

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1i don't think I followed you this time. How come your y came from denominator to numerator?

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1\(\large\color{black}{ \displaystyle x=\frac{2\pm\sqrt{44(1)(\frac{1}{y})}}{2} }\) \(\large\color{black}{ \displaystyle x=\frac{2\pm\sqrt{4+4(\frac{1}{y})}}{2} }\) it should be like this

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1it can be simplified ....

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1\(\large\color{black}{ \displaystyle x=\frac{2\pm\sqrt{4+4(\frac{1}{y})}}{2} }\) \(\large\color{black}{ \displaystyle x=\frac{2\pm2\sqrt{1+(\frac{1}{y})}}{2} }\) \(\large\color{black}{ \displaystyle x=1\pm\sqrt{1+\frac{1}{y}} }\)

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1this is it, technically, although, if you feel like or need to you can rationalize the denominator
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