A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
Please help....
If x>0, and two sides of a certain triangle have lengths 2x+1 and 3x+4 respectively, which of the following could be the length of the third side of the triangle?
anonymous
 one year ago
Please help.... If x>0, and two sides of a certain triangle have lengths 2x+1 and 3x+4 respectively, which of the following could be the length of the third side of the triangle?

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The third side of the triangle must have a length greater than zero and less than the sum of the other two sides.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.01. 4x+5 2. x+2 3. 6x+1 4. 5x+6 5. 2x+17

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i know its 1, 3 and 5 but why is 3 an answer?

welshfella
 one year ago
Best ResponseYou've already chosen the best response.1adding the 2 given sides gives 5x + 5

ali2x2
 one year ago
Best ResponseYou've already chosen the best response.0Note x>0 says 3x+4 > 2x+1. So, the possibilities are those which lie between the following sum and difference: (3x+4) + (2x+1) = 5x+5 (3x+4)  (2x+1) = x+3

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0If you add the length of the two sides together, you get \(5x+5\). Set that equal to \(6x+1\) and solve for \(x\). Is \(x > 0\) ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but look at B if you use 10 then it also doesn't work out

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it COULD BE if, for example, \(x=1\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[5x + 5 = x+2\]\[4x = 3\]Can that be?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hmmm i see wow so i'd have to be extra extra careful..... this question is a tricky one

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i have to add that this is, in my opinion ,a really foolish question that confuses the issue

welshfella
 one year ago
Best ResponseYou've already chosen the best response.1for arguments sake let x = 2 5x + 5 = 15 6x + 1 = 13 so 3rd side is less than sum of the other 2 6x +1 can be the third side.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Satellite i 1000000% agree and the only reason it's such a dumb question is because it's a GRE question.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah standardized tests strike again

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay got it thanks everyone =)

phi
 one year ago
Best ResponseYou've already chosen the best response.0I would do it this way: from 2x+1 and 3x+4 , we must be > x+3 and < 5x+5 1. x+3 < 4x+5 < 5x+5 4x>x and 5>3 and 4x<5x and 5=5. this is OK 2. x+3 < x+2 < 5x+5 for all x>0, x+3 is bigger than x+2. NOT legal 3. x+3 <6x+1 < 5x+5 x+3< 6x+1 means 2 < 5x, 2/5 < x and 6x+1 < 5x + 5 means x< 4. so : 2/5 < x < 4 works. OK 4. x+3 <5x+6 < 5x+5 for all x>0 5x+6 > 5x+5. NOT legal 5. x+3 < 2x+17< 5x+5 2x>x and 17>3 . also 2x+17<5x+5 means 12<3x, 4<x so for x>4 this is OK

phi
 one year ago
Best ResponseYou've already chosen the best response.0when I checked (for example) x+3 < 4x+5 I said it is obviously true for x>0 but we could analyze it by simplifying the relation to 2 < 3x (add x to both sides, add 5 to both sides) 2/3 < x and it is true for all x > 2/3. because x>0, this will always be true.

phi
 one year ago
Best ResponseYou've already chosen the best response.0and if we wanted to analyze x+3 < x+2 add x to both sides 3<2 and we see this is not true. thus we could simplify each relation and make sure it is true for some x
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.