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anonymous
 one year ago
2 men and 3 boys can do a piece of work in 10 days while 3 men and 2 boys can do the same work in 8 days. In how many days can 2 men and 1 boy do the work?
ans is 8 or 12.5?
anonymous
 one year ago
2 men and 3 boys can do a piece of work in 10 days while 3 men and 2 boys can do the same work in 8 days. In how many days can 2 men and 1 boy do the work? ans is 8 or 12.5?

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vanessaperezxo
 one year ago
Best ResponseYou've already chosen the best response.0I think the answer would be 12.5

vanessaperezxo
 one year ago
Best ResponseYou've already chosen the best response.0because for it to be done in 8 day you need 3 men and 2 boys.. so if you have 2 men 1 boy it's going to take a few extra days. Do you get it? @yashiii

vanessaperezxo
 one year ago
Best ResponseYou've already chosen the best response.0@yashiii you there?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yup....i think i solved it incorrectly .my ans was 8 ..hehhe

vanessaperezxo
 one year ago
Best ResponseYou've already chosen the best response.0Oh ok, i have to go. Good luck solving the problem. sorry

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0bye :) @vanessaperezxo

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1If I call with x the working rate of a man, and with y the working rate of a boy, then I can write this algebraic system: \[\Large \left\{ \begin{gathered} 2x + 3y = \frac{W}{{10}} \hfill \\ 3x + 2y = \frac{W}{8} \hfill \\ \end{gathered} \right.\] where W is the work to be done

phi
 one year ago
Best ResponseYou've already chosen the best response.02 men and 3 boys can do a piece of work in 10 days 2 men and 1 boy will take longer (less help) so if it's a choice between 8.5 and 12.5, pick 12.5

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0a similar approach is to solve \[10(2x+3y)=1\\ 8(3x+2y)=1\] which is not that elegant but works

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but as @phi said, common sense tells you it is longer than 8 it is in fact 12.5

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0actually i want correct ans...those ans options were imaginary .:(

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how did you guess at the correct answer of 12.5?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0now i got ans 13.5 , so any one can pls tell me the accurate ans

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@satellite73 , on any website someone solved it ,but other people were saying that ans is wrong. so m confused

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0we can do it step by step, although i guess there probably a better method than i used

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0put men's rate as x, boys at y the first two statements translates as \[10(2x+3y)=1\\ 8(3x+2y)=1\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0solving this for x and y gives \[x=\frac{7}{200},y=\frac{1}{100}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Michele_Laino , you have ne idea

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0acha..okay..got it now :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oops i means solve \[T\left(\frac{14}{200}+\frac{1}{100}\right)=1\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and that gives \(T=12.5\)

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1I agree with @satellite73 we have to solve that system above, so we can find the requested time

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0like i said, there may be a snappier way to do it, i don't know it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@satellite73 , @Michele_Laino , thankyou so much both of you :)
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