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monkey*

  • one year ago

Can anyone help with Precalculus?

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  1. monkey*
    • one year ago
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    Find an equation in slope-intercept form of the line that has slope 5 and passes through point A (4,-5) Y=5x+25 Y=-5x-25 Y=25x-5 Y=5x-25

  2. Mehek14
    • one year ago
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    so lets try A

  3. Mehek14
    • one year ago
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    put 4 for x and -5 for y \(-5= 5*4 +25\) tell me if it's tru

  4. SolomonZelman
    • one year ago
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    Mehek, if slope is 5, then it is just 5x (not -5x). For any slope m it would be mx

  5. Mehek14
    • one year ago
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    true*

  6. SolomonZelman
    • one year ago
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    y=mx+b -5=(5)4+b -5=20+b b=-25 y=5x-25

  7. SolomonZelman
    • one year ago
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    I don't get why is it precalculus though, if it is algebra

  8. Mehek14
    • one year ago
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    it is Algebra

  9. Mehek14
    • one year ago
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    @monkey* have you tried solving it?

  10. monkey*
    • one year ago
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    Most of my problems are like this. And yes @mehek14. So I would use y=mx+b, right?

  11. Mehek14
    • one year ago
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    correct

  12. Mehek14
    • one year ago
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    so plug in the ordered pairs and see which equation goes with it

  13. monkey*
    • one year ago
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    Okay, one minute.

  14. monkey*
    • one year ago
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    It would be y=5x-25?

  15. Mehek14
    • one year ago
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    correct \(\ddot\smile\)

  16. monkey*
    • one year ago
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    Thank you! Would you mind helping with a few more?

  17. Mehek14
    • one year ago
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    sure

  18. monkey*
    • one year ago
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    Okay. Write an equation in standard form the passes through points (-4,10) and (0,-5).

  19. monkey*
    • one year ago
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    Start me off? I'll figure it out from there.

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