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Testing123guest

  • one year ago

plz help for medal @Michele_Laino

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  1. Testing123guest
    • one year ago
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  2. Michele_Laino
    • one year ago
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    If I call with N the missing exponent, we can write this: \[\Large {\left( {{2^{ - 5}}} \right)^N} = {2^{ - 15}}\] and subsequently I apply the rule of power of power, so I get this condition: \[\Large - 5 \cdot N = - 15\] what is N?

  3. Testing123guest
    • one year ago
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    -3?

  4. Michele_Laino
    • one year ago
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    I think no, since: -5 * -3= +15

  5. Testing123guest
    • one year ago
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    -5 * 3 = -15

  6. Michele_Laino
    • one year ago
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    correct! it is N=3

  7. Testing123guest
    • one year ago
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    thanks man u rock i will talk to u tomorrow i am going t hop off my computer

  8. Michele_Laino
    • one year ago
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    ok! :)

  9. Testing123guest
    • one year ago
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    wait i have one more question sorry

  10. Michele_Laino
    • one year ago
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    ok! I'm ready!

  11. Testing123guest
    • one year ago
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  12. Michele_Laino
    • one year ago
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    We can rewrite your expression as below: \[\Large \frac{{{7^{ - 3}} \cdot {7^9}}}{{{7^{ - 8}}}} = {7^{ - 3}} \cdot {7^9} \cdot {7^8}\] Now I apply the rule of multiplication of power with the same basis, so I get: \[\Large \frac{{{7^{ - 3}} \cdot {7^9}}}{{{7^{ - 8}}}} = {7^{ - 3}} \cdot {7^9} \cdot {7^8} = {7^{ - 3 + 9 + 8}} = ...?\]

  13. Testing123guest
    • one year ago
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    363?

  14. Testing123guest
    • one year ago
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    sorry my computer froze

  15. Michele_Laino
    • one year ago
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    what is -3+9+8=...?

  16. Testing123guest
    • one year ago
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    14

  17. Michele_Laino
    • one year ago
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    correct! so what is the right option?

  18. Testing123guest
    • one year ago
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    D?

  19. Michele_Laino
    • one year ago
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    option D is not \[\Large {7^{14}}\]

  20. Michele_Laino
    • one year ago
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    you have to search for \[\Large {7^{14}}\]

  21. Testing123guest
    • one year ago
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    positive 14 or negative 14

  22. Michele_Laino
    • one year ago
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    -3+9+8= +14 so?

  23. Testing123guest
    • one year ago
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    a

  24. Michele_Laino
    • one year ago
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    yes!

  25. Testing123guest
    • one year ago
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    u rock

  26. Michele_Laino
    • one year ago
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    thanks! :)

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