Testing123guest
  • Testing123guest
plz help for medal @Michele_Laino
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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Testing123guest
  • Testing123guest
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Michele_Laino
  • Michele_Laino
If I call with N the missing exponent, we can write this: \[\Large {\left( {{2^{ - 5}}} \right)^N} = {2^{ - 15}}\] and subsequently I apply the rule of power of power, so I get this condition: \[\Large - 5 \cdot N = - 15\] what is N?
Testing123guest
  • Testing123guest
-3?

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More answers

Michele_Laino
  • Michele_Laino
I think no, since: -5 * -3= +15
Testing123guest
  • Testing123guest
-5 * 3 = -15
Michele_Laino
  • Michele_Laino
correct! it is N=3
Testing123guest
  • Testing123guest
thanks man u rock i will talk to u tomorrow i am going t hop off my computer
Michele_Laino
  • Michele_Laino
ok! :)
Testing123guest
  • Testing123guest
wait i have one more question sorry
Michele_Laino
  • Michele_Laino
ok! I'm ready!
Testing123guest
  • Testing123guest
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Michele_Laino
  • Michele_Laino
We can rewrite your expression as below: \[\Large \frac{{{7^{ - 3}} \cdot {7^9}}}{{{7^{ - 8}}}} = {7^{ - 3}} \cdot {7^9} \cdot {7^8}\] Now I apply the rule of multiplication of power with the same basis, so I get: \[\Large \frac{{{7^{ - 3}} \cdot {7^9}}}{{{7^{ - 8}}}} = {7^{ - 3}} \cdot {7^9} \cdot {7^8} = {7^{ - 3 + 9 + 8}} = ...?\]
Testing123guest
  • Testing123guest
363?
Testing123guest
  • Testing123guest
sorry my computer froze
Michele_Laino
  • Michele_Laino
what is -3+9+8=...?
Testing123guest
  • Testing123guest
14
Michele_Laino
  • Michele_Laino
correct! so what is the right option?
Testing123guest
  • Testing123guest
D?
Michele_Laino
  • Michele_Laino
option D is not \[\Large {7^{14}}\]
Michele_Laino
  • Michele_Laino
you have to search for \[\Large {7^{14}}\]
Testing123guest
  • Testing123guest
positive 14 or negative 14
Michele_Laino
  • Michele_Laino
-3+9+8= +14 so?
Testing123guest
  • Testing123guest
a
Michele_Laino
  • Michele_Laino
yes!
Testing123guest
  • Testing123guest
u rock
Michele_Laino
  • Michele_Laino
thanks! :)

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