Destinyyyy
  • Destinyyyy
Help..
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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Destinyyyy
  • Destinyyyy
-20+ square root -50/60
SolomonZelman
  • SolomonZelman
\(\large\color{black}{ \displaystyle -20+\sqrt{-\frac{50}{60}~\color{white}{\Huge|}} }\) like this?
Destinyyyy
  • Destinyyyy
the 60 is under the whole equation

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SolomonZelman
  • SolomonZelman
\(\large\color{black}{ \displaystyle \frac{-20+\sqrt{-50}}{60} }\)
SolomonZelman
  • SolomonZelman
lihe that \(\Uparrow\) ?
SolomonZelman
  • SolomonZelman
like*
Destinyyyy
  • Destinyyyy
Yes
SolomonZelman
  • SolomonZelman
\(\large\color{black}{ \displaystyle \frac{-20\color{red}{\pm}\sqrt{-50}}{60} }\) It doesn't have that ± sign, right?
Destinyyyy
  • Destinyyyy
Nope just plus
SolomonZelman
  • SolomonZelman
oh. ok
SolomonZelman
  • SolomonZelman
\(\large\color{black}{ \displaystyle \frac{-20+\sqrt{-50}}{60} }\) \(\large\color{black}{ \displaystyle \frac{-20}{60}+\frac{\sqrt{-50}}{60} }\)
SolomonZelman
  • SolomonZelman
so, so far will just say: \(\large\color{black}{ \displaystyle -\frac{1}{3}+\frac{\sqrt{-50}}{60} }\) and now will deal with the second part with the square root.
SolomonZelman
  • SolomonZelman
\(\large\color{black}{ \displaystyle -\frac{1}{3}+\frac{\sqrt{(-1)\cdot 25\cdot2}}{60} }\) can you simplfiy that?
Destinyyyy
  • Destinyyyy
5i square root 2 / 12
SolomonZelman
  • SolomonZelman
when you take the 25 out of the square root it becomes 5, because: \(\large\color{black}{ \displaystyle -\frac{1}{3}+\frac{\sqrt{(-1)\cdot 25\cdot2}}{60} }\) \(\large\color{black}{ \displaystyle -\frac{1}{3}+\frac{\sqrt{(-1)}\cdot\sqrt{ 25}\cdot\sqrt{ 2}}{60} }\) \(\large\color{black}{ \displaystyle -\frac{1}{3}+\frac{i\cdot\sqrt{ 5^2}\cdot\sqrt{ 2}}{60} }\) \(\large\color{black}{ \displaystyle -\frac{1}{3}+\frac{5i\sqrt{ 2}}{60} }\)
SolomonZelman
  • SolomonZelman
and then divide by 5. Am I making sense?
Destinyyyy
  • Destinyyyy
Yeah.. So i square root 2 over 12
SolomonZelman
  • SolomonZelman
yes, so altogether: \(\large\color{black}{ \displaystyle -\frac{1}{3}+\frac{i\sqrt{ 2}}{12} }\)
SolomonZelman
  • SolomonZelman
and if you want it in a+bi form, then \(\large\color{black}{ \displaystyle -\frac{1}{3}+\frac{\sqrt{ 2}}{12}i }\)
SolomonZelman
  • SolomonZelman
which is same..........................................
Destinyyyy
  • Destinyyyy
Yup.. Thank you.
SolomonZelman
  • SolomonZelman
yw

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