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-20+ square root -50/60
\(\large\color{black}{ \displaystyle -20+\sqrt{-\frac{50}{60}~\color{white}{\Huge|}} }\) like this?
the 60 is under the whole equation

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\(\large\color{black}{ \displaystyle \frac{-20+\sqrt{-50}}{60} }\)
lihe that \(\Uparrow\) ?
like*
Yes
\(\large\color{black}{ \displaystyle \frac{-20\color{red}{\pm}\sqrt{-50}}{60} }\) It doesn't have that ± sign, right?
Nope just plus
oh. ok
\(\large\color{black}{ \displaystyle \frac{-20+\sqrt{-50}}{60} }\) \(\large\color{black}{ \displaystyle \frac{-20}{60}+\frac{\sqrt{-50}}{60} }\)
so, so far will just say: \(\large\color{black}{ \displaystyle -\frac{1}{3}+\frac{\sqrt{-50}}{60} }\) and now will deal with the second part with the square root.
\(\large\color{black}{ \displaystyle -\frac{1}{3}+\frac{\sqrt{(-1)\cdot 25\cdot2}}{60} }\) can you simplfiy that?
5i square root 2 / 12
when you take the 25 out of the square root it becomes 5, because: \(\large\color{black}{ \displaystyle -\frac{1}{3}+\frac{\sqrt{(-1)\cdot 25\cdot2}}{60} }\) \(\large\color{black}{ \displaystyle -\frac{1}{3}+\frac{\sqrt{(-1)}\cdot\sqrt{ 25}\cdot\sqrt{ 2}}{60} }\) \(\large\color{black}{ \displaystyle -\frac{1}{3}+\frac{i\cdot\sqrt{ 5^2}\cdot\sqrt{ 2}}{60} }\) \(\large\color{black}{ \displaystyle -\frac{1}{3}+\frac{5i\sqrt{ 2}}{60} }\)
and then divide by 5. Am I making sense?
Yeah.. So i square root 2 over 12
yes, so altogether: \(\large\color{black}{ \displaystyle -\frac{1}{3}+\frac{i\sqrt{ 2}}{12} }\)
and if you want it in a+bi form, then \(\large\color{black}{ \displaystyle -\frac{1}{3}+\frac{\sqrt{ 2}}{12}i }\)
which is same..........................................
Yup.. Thank you.
yw

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