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anonymous
 one year ago
Solve for x. Round your answer to 2 decimal places.
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anonymous
 one year ago
Solve for x. Round your answer to 2 decimal places. (picture below) ** medal & fan

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Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.0do you know what the law of sines is?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0um, i dont think i have covered that yet.

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.0Does this look familiar to you at all? \(\large\frac{a}{Sin A}=\large\frac{b}{Sin B}=\large\frac{c}{Sin C}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no, i definitely have not covered that yet :(

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.0fair enough. I'm not sure how I would solve a problem like this without that, sorry

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1440460690118:dw recall you SOH CAH TOA \(\bf sin(\theta)=\cfrac{opposite}{hypotenuse} \qquad \qquad % cosine cos(\theta)=\cfrac{adjacent}{hypotenuse} \\ \quad \\ % tangent tan(\theta)=\cfrac{opposite}{adjacent}\) which identity uses the angle adjacent side, and hypotenuse only?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeap thus... one sec

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i will wait for you :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\(\bf cos(\theta)=\cfrac{adjacent}{hypotenuse}\implies hypotenuse=\cfrac{adjacent}{cos(\theta)}\qquad thus \\ \quad \\ cos(58^o)=\cfrac{17}{x}\implies x=\cfrac{17}{cos(48^o)} \)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hmmm my 58 turned into a 48 for whatever reason =) \(\bf cos(\theta)=\cfrac{adjacent}{hypotenuse}\implies hypotenuse=\cfrac{adjacent}{cos(\theta)}\qquad thus \\ \quad \\ cos(58^o)=\cfrac{17}{x}\implies x=\cfrac{17}{cos(58^o)}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0notice, you're using degrees, thus, make sure your calculator is in Degree mode when getting the cosine

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i got it!! thank you so much!! that was really simple!!
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