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anonymous
 one year ago
Which of the following correctly uses absolute value to show the distance between –80 and 15?
–80 – 15 = –95 = –95 units
–80 + 15 = –65 = 65 units
–80 – 15 = –95 = 95 units
–80 + 15 = –65 = –65 units
anonymous
 one year ago
Which of the following correctly uses absolute value to show the distance between –80 and 15? –80 – 15 = –95 = –95 units –80 + 15 = –65 = 65 units –80 – 15 = –95 = 95 units –80 + 15 = –65 = –65 units

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0whatever you call it, its the third one

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0draw a number line dw:1440462021959:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0let's say there are 2 points x and y on it dw:1440462049281:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0the distance from x to y, or vice versa, is going to be equal to xy or yx

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0dw:1440462084438:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0the absolute value bars ensure the distance is never negative
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