Algebraically determine the domain and range: y=x^2-8x+7

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

Algebraically determine the domain and range: y=x^2-8x+7

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

i already know the domain just need help with the range
have you learned about completing the square?
Yes

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

wait you got x you said right?
\[x=y^2-8y+7\]
And yes
complete the square to get the equation into vertex form y = a(x-h)^2 + k the range will be \(\Large y \ge k\) (replace k with a numeric value though) because 'a' is positive which means the parabola opens upward
I was taught to substitute the x for the y and vice vera
@jim_thompson5910 can't he use substitution?
@JacksonJRB you're thinking of the inverse
Ah
first compute h = -b/(2a) in this case, a = 1, b = -8
there might be an easier way x^2-8x+7 is factorabole y=x^2-8x+7 you can find the average of the 0's so the 0's are a and b the average of a and b is (a+b)/2 so you can find the range by doing: \[[f(\frac{a+b}{2}),\infty) \text{ since } a=1>0\]
once you know the value of h, plug it into y=x^2-8x+7 to find k
y-value of the vertex (the k of the vertex) is the minimum range. (and there is no maximum limit for range) no range limits, since it is a polynomial
`can't he use substitution?` I'm not sure what you mean @GTA_Hunter35
he said he has x
He said he had the domain. Not just a single value of x.
nvm it won't work
^^
^_^
its your call @jim_thompson5910
I'm still very confused...
were you able to compute h = -b/(2a) ?
do you want to complete the square or find the zeros or use the vertex formula?
what value did you get for h
wait wats the vertex formula?
And either way @freckles
h=4
well if you find the average of the zeros you will find the x-coordinate of the vertex
plug x = 4 into y=x^2-8x+7 and you get y = ??
nevermind you guys got the x-coordinate of the vertex
-9
so k = -9 making the range \(\Large y \ge -9\) we have a parabola that has the lowest point at (4,-9). All other points will have larger y values.
Ah. That makes sense now. Thank you so much!
no problem
\[f(x)=x^2-8x+7 \\ f(x)=(x-7)(x-1) \\ f(x)=0 \text{ when } x=1 \text{ or } x=7 \\ \text{ the average of the zeros is } \frac{7+1}{2}=\frac{8}{2}=4 \\ \text{ so since } a=1>0 \text{ then the range is } [f(4),\infty) \\ f(4)=4^2-8(4)+7=-9 \\ \text{ so the range is } [-9,\infty)\] just wanted to type what I was going for
well ur right too but u used the function way
used the function way?
u used f of x
dat was the only difference
k

Not the answer you are looking for?

Search for more explanations.

Ask your own question