Anyone know how to do this? Choose the equation below that represents the line passing through the point (−2, −3) with a slope of −6. y + 3 = −6(x + 2) y + 2 = 6(x + 3) y − 3 = −6(x − 2) y − 2 = 6(x − 3)

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Anyone know how to do this? Choose the equation below that represents the line passing through the point (−2, −3) with a slope of −6. y + 3 = −6(x + 2) y + 2 = 6(x + 3) y − 3 = −6(x − 2) y − 2 = 6(x − 3)

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|dw:1440465566559:dw|
The slope is -6, so m = -6 |dw:1440465619033:dw|
the given point is (-2,-3) so x1 = -2 and y1 = -3 |dw:1440465654663:dw|

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after you do those three replacements, you will get |dw:1440465690001:dw|
be very careful how the substitutions are made eg: notice how I didn't say y - 3. I said y - (-3)
the last step is to simplify which I'll let you do
@jim_thompson5910 Sorry I was playing league. How would I simplify this? y + 3 = −6(x + 2) Right?
correct

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