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kmullis6
 one year ago
Please help, I'll give fan & medal
kmullis6
 one year ago
Please help, I'll give fan & medal

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kmullis6
 one year ago
Best ResponseYou've already chosen the best response.0Directions: Complete the conjecture based on the pattern you observe in the specific cases. Conjecture: The product of a number (n  1) and the number (n +1) is always equal to _____. \[3\times5=4^{2}1\] \[4\times6=5^{2}1\] \[5\times7=5^{2}1\] \[6\times8=7^{2}1\] \[7\times9=8^{2}1\] \[8\times10=9^{2}1\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1it is not clear? what do you think \[9\times 11\]would equal in that pattern?

kmullis6
 one year ago
Best ResponseYou've already chosen the best response.099 so odd number. that's the types of questions i'm answering right now.

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1lets look more carefully

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1the right hand side of each equal sign is some number squared minus 1 right?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1and that number, the number being squared, is half way between the other two numbers right?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1the number in the middle of \(n1\) and \(n+1\) is just \(n\)

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1so what they are showing you, by example instead of by algebra, is that \[(n1)(n+1)=n^21\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1lol no, the answer is \(n^21\)

kmullis6
 one year ago
Best ResponseYou've already chosen the best response.0oohhhh ok. sorry haha :P thank you (:
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