anonymous
  • anonymous
okay so for point S would it be SOH: 3/5 CAH: 4/5 TOA: 3/2
Mathematics
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
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misty1212
  • misty1212
HI!!
misty1212
  • misty1212
last one is wrong i think

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misty1212
  • misty1212
\[\frac{\text {opposite}}{\text{adjacent}}\]
anonymous
  • anonymous
HIII lol oh really? hmm what would it be then?
misty1212
  • misty1212
what is the length of the side opposite angle S?
misty1212
  • misty1212
btw i think you probably just reduced wrong
jim_thompson5910
  • jim_thompson5910
sin(S) = 3/5 ... true cos(S) = 4/5 ... true tan(S) = 3/2 ... false
anonymous
  • anonymous
oh hmm do you know what i did wrong @jim_thompson5910
jim_thompson5910
  • jim_thompson5910
follow what @misty1212 gave you tan(angle) = opposite/adjacent
jim_thompson5910
  • jim_thompson5910
in this case, the opposite is 6, the adjacent is 8 so reduce 6/8 to get ???
misty1212
  • misty1212
hint, it is not \(\frac{3}{2}\)
anonymous
  • anonymous
ohh so it would be 3/4
jim_thompson5910
  • jim_thompson5910
yes tan(S) = 3/4
anonymous
  • anonymous
Okidoki thanks :P
jim_thompson5910
  • jim_thompson5910
no problem

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