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kenialove

  • one year ago

A cone has a height of 24 inches , a slant height of 25 inches , and a diameter of 14 inches. What is the surface area of the cone ? A. 1,176 pi^2 B. 392 pi^2 C. 224 pi^2 D. 178 pi^2 I know how to plug in the numbers and everything but I forgot the formula to find my answer .. Can someone help me ?

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  1. jim_thompson5910
    • one year ago
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    The surface area of a cone is \[\Large SA = \pi*r^2 + \pi*r*s\] SA = surface area r = radius s = slant height

  2. jim_thompson5910
    • one year ago
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    In this problem, r = 7 since the diameter is 14 and you cut the diameter in half to get the radius. Also, s = 25 is the slant height.

  3. kenialove
    • one year ago
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    Thanks so much

  4. kenialove
    • one year ago
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    So it would be .. A = 3.14 x 7^2 + 3.14 x 7 x 25

  5. kenialove
    • one year ago
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    I got the answer 703.36 but that's not one of the choices in the question .. Can u help me ? @jim_thompson5910

  6. jim_thompson5910
    • one year ago
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    leave pi as it is

  7. jim_thompson5910
    • one year ago
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    think of pi as a variable if you have to

  8. kenialove
    • one year ago
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    Okay I'll try that

  9. jim_thompson5910
    • one year ago
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    tell me what you get

  10. kenialove
    • one year ago
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    I think I need help cause I'm getting a bigger number

  11. jim_thompson5910
    • one year ago
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    what is 7^2 equal to?

  12. kenialove
    • one year ago
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    49

  13. jim_thompson5910
    • one year ago
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    how about 7*25, what is that equal to?

  14. kenialove
    • one year ago
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    175

  15. jim_thompson5910
    • one year ago
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    So... \[\Large SA = \pi*r^2 + \pi*r*s\] \[\Large SA = \pi*7^2 + \pi*7*25\] \[\Large SA = \pi*49 + \pi*175\] \[\Large SA = 49\pi + 175\pi\] \[\Large SA = 224\pi\]

  16. jim_thompson5910
    • one year ago
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    notice how I added 49pi to 175pi to get 224pi similar to me saying 49x+175x = 224x

  17. kenialove
    • one year ago
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    Ohhh I know where I missed up Thanks so much

  18. jim_thompson5910
    • one year ago
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    glad to be of help

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