anonymous
  • anonymous
Describe a method you can use to find the area of the following shape. Provide specific details in your answer, including coordinates and descriptions of shapes used. Then, find the actual area of the figure.
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
@zepdrix
anonymous
  • anonymous
@ganeshie8

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

zepdrix
  • zepdrix
Hey :) So umm.. how bout break it up into some more manageable shapes?
anonymous
  • anonymous
okay, how should we start doing that?
zepdrix
  • zepdrix
|dw:1440473225733:dw|
anonymous
  • anonymous
Are we wanting to divide it into 3 shapes or just however many we can make ?
zepdrix
  • zepdrix
Well I'm thinking like this maybe:|dw:1440473387371:dw|because rectangles and right triangles are really easy to deal with :)
zepdrix
  • zepdrix
Do you understand how to find the coordinates of each point?
zepdrix
  • zepdrix
Or rather I should say: Do you understand how to use the coordinates to find the side lengths?
anonymous
  • anonymous
Okay(: So what is our first step? sorry im really not good at this. I think so isn't that do you count like up and down along y axis and and left to right on x axis ?
zepdrix
  • zepdrix
`Provide specific details in your answer, including coordinates and descriptions of shapes used. Then, find the actual area of the figure.` Yes, counting the squares is a much better way of doing it, but it looks like they want us to include coordinates and all of that business :(
anonymous
  • anonymous
ughh :( okay so then how do we do that ?
zepdrix
  • zepdrix
|dw:1440473666198:dw|Do you understand how I came up with these two coordinates?
anonymous
  • anonymous
For B you counted up 8 and counted left 11 units For C you counted left 11 units but the zero you didnt move at all ?
zepdrix
  • zepdrix
Yes, those distances. But your 'directions' seem backwards lol :) For B you count 8DOWN and 11RIGHT. We're starting from the point (0,0) and going towards B. I think you did it the other way around.
zepdrix
  • zepdrix
Oh boy this is gonna be tricky... I wonder if there is a simpler way we can chop this up...
anonymous
  • anonymous
Oh your right i did my bad lol(: Hmmm could we do AC and that be a right triangle ? would that be an easier way to chop it up ?
zepdrix
  • zepdrix
|dw:1440474034288:dw|Hmm prolly not :) that leaves us with a nasty shape here
zepdrix
  • zepdrix
Are you comfortable with trapezoids?
zepdrix
  • zepdrix
|dw:1440474081780:dw|Cause maybe this would be easier
anonymous
  • anonymous
kinda , im deffinetly gonna need help though
anonymous
  • anonymous
So does that mean what we did with B and C earlier...forget that ?
zepdrix
  • zepdrix
It'll end up saving us some steps since we don't have to find all these little shapes in the middle. Just three now. To find the area of a trapezoid, we multiply the base length by the average of the side/height lengths.\[\large\rm A=b\cdot\frac{h_1+h_2}{2}\] How long is side BC?
anonymous
  • anonymous
I thought 11 units , correct?
zepdrix
  • zepdrix
|dw:1440474292576:dw|I'm just gonna label all of the points that we'll need.
zepdrix
  • zepdrix
|dw:1440474388966:dw|
zepdrix
  • zepdrix
from 0 down to -8
anonymous
  • anonymous
so would the height be -8 and 0 for BC
zepdrix
  • zepdrix
The height is the distance from 0 to -8. That ends up being a distance of 8 if you count the boxes, ya?
anonymous
  • anonymous
Yes your right, im just trying to plug in the h1 and h2 too quick lol sorry
zepdrix
  • zepdrix
|dw:1440474556848:dw|How bout from D down the bottom? You're at -3 and you're going down to -8, how many boxes between those?
zepdrix
  • zepdrix
Make sure you're using the original image :) Mine kinda stinks since you can't count the boxes lol
anonymous
  • anonymous
Okay(: Would that be 5?
zepdrix
  • zepdrix
|dw:1440474733035:dw|Good :O Then the base? Looks like we're going from x=6 over to x=11
anonymous
  • anonymous
would the base be 6?
zepdrix
  • zepdrix
We're going from 6 to 11. You can do subtraction if you feel more comfortable with that. 11-6 = 5 So a length of 5 across the bottom.
anonymous
  • anonymous
Okay i must have counted wrong, so now i plug in the numbers?
zepdrix
  • zepdrix
\[\large\rm A=b\cdot\frac{h_1+h_2}{2}\qquad\to\qquad A_1=5\cdot\frac{5+8}{2}\]Plug all the information in! :) What do we get for the area of our first shape? Yah sorry I stole some of the fun there, just trying to move this along hehe.
anonymous
  • anonymous
Haha its okay(: so then it would be 13/2 = 6.5 then 6.5 X5 = 32.5 SO would our answer be 32.5?
zepdrix
  • zepdrix
|dw:1440475130927:dw|Ok great! We're 1/3 done lol
anonymous
  • anonymous
Great(: ! So now do we do the same thing to the other shape ?
zepdrix
  • zepdrix
Let's ignore the coordinates for now. Just use those in your explanation maybe :p|dw:1440475216912:dw|
zepdrix
  • zepdrix
Yes, let's work on this trapezoid in the bottom left here. Can you figure out the side lengths by counting the boxes?
anonymous
  • anonymous
That would be 2 if your counting up and if your counting left then that would be 5
zepdrix
  • zepdrix
Hmm 5 doesn't sound quite right.
anonymous
  • anonymous
Then im confused i counted to the F and it was 5 units
zepdrix
  • zepdrix
|dw:1440475453452:dw|
anonymous
  • anonymous
Oh i see my mistake, i moissed one, my bad :/
zepdrix
  • zepdrix
So we have our information again, good. \(\large\rm h_1=1,\quad h_2=6,\quad b=2\) plug it in to find the area of your second shape.
anonymous
  • anonymous
One question first, how did you get the 1?
anonymous
  • anonymous
A = 7?
zepdrix
  • zepdrix
|dw:1440475703801:dw|
zepdrix
  • zepdrix
So that length is 1 from 5 to 6, ya? :o
anonymous
  • anonymous
Oh yeah your right , duhhh(: so my answer would be 7 correct ?
zepdrix
  • zepdrix
|dw:1440475843531:dw|Mmmmmm k good. let's try to figure out this last one. Luckily we have a free side already! Since this trapezoid shares a side with the bottom one, we know that the long edge is still 6.
zepdrix
  • zepdrix
What about the other lengths? :o
anonymous
  • anonymous
well from D to E that would be 2
anonymous
  • anonymous
the other length would be 3
zepdrix
  • zepdrix
|dw:1440476101788:dw|Ok good! :)
anonymous
  • anonymous
h1 = 3 h2 = 6 b=2?
zepdrix
  • zepdrix
The h's should be across from one another.
anonymous
  • anonymous
b= 3 and h2= 2
anonymous
  • anonymous
Im sorry , for the confusion im just trying to understand .. so the answer would be 12?
zepdrix
  • zepdrix
|dw:1440476358788:dw|Good. And the total area would be the sum of those three areas. \(\large\rm A=A_1+A_2+A_3\)
zepdrix
  • zepdrix
yayyyy team \c:/ we did it!
anonymous
  • anonymous
51.5 ??
zepdrix
  • zepdrix
sounds correct!
anonymous
  • anonymous
Yayyyy(: thank you soooo much for your help i really really appreciate it!

Looking for something else?

Not the answer you are looking for? Search for more explanations.